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4 years ago

T object]user: a ____ farm can be used to generate electricity

1 answer:

4 0

Large fields of windmills or solar panels can be used
to collect enough energy to power a whole town.

These are sometimes called "wind farms" or "solar farms".

You might be interested in

You carry a 50 N backpack for 10000 meters in 500 secs. How much power did you use?

Klio2033 [76]

<h2>for cara a 50+10000=9768m in for 500×9768=586858metres </h2>

5 0

3 years ago

What two factors keep Earth in orbit and around the sun and the moon in orbit around Earth?

Alex_Xolod [135]

D because bits makes the most sense logically

8 0

4 years ago

Read 2 more answers

A 30 kg child sitting 5.0 m from the center of a merry-go-round has a constant speed of 5.0 m/s. while she remains seated in the

expeople1 [14]

Let us say that v is the tangential velocity of the object, a to be the centripetal (which acts towards the center of the circle) acceleration and F as the centripetal force, r to be the radius of the circle and m is mass of the child. 

a = v^2 / r

F = ma = mv^2/r

Applying the given values to the equation:

F=30*(5^2/5) => 30*(25/5) => 30*5 => 150 Newtons

Now work is Force times distance, the distance is simply the circumference of the circle.

d = C = 2 * pi * r = 2 * pi * 5 = 10π m

W = F * d = 150 N * 10π m

W = 1500π J = 4712.39 J

8 0

3 years ago

A child holds onto a string attached to a toy boat and exerts a force of 7.5 N to pull the boat a distance of 9.2 m a long a str

soldi70 [24.7K]

The work that need to do is 66.24 J.

<h3>Explanation :</h3>

Hello guys, before we can count how much the work that needed to pull the toy, we should know how formula to count it first. Because the movement is with the angle, so the formula is :

$\boxed {\bold {W = F \times s \times \cos(\theta)}}$

If :

W = work (J)
F = force (N)
s = shift (m)
θ = elevation angle (°)

We know that :

x = the horizontal shift = 9,2 m
θ = elevation angle = 15°

W = work = ... J

$W = F \times s \times \cos(\theta) \\ W = 7.5 \times 9.2 \times \cos(15) \\ W = 69 \times 0.96 = 66.24 \: J$

So, the work that need to do is 66.24 J.

Subject : Physics 

Class : Junior High School/Senior High School 

Keyword : Work; Force; Shift; and Elevation Angle 

5 0

4 years ago

What happens to a light ray if it is incident on a reflective surface along the normal?

Bad White [126]

Answer: The incident ray and the reflected ray and the normal will be parallel to each other.

Explanation:

The normal is perpendicular to the surface of the mirror or the reflective surface.

According to the law of reflection which state that:

The angle of incidence is always equal to the angle of reflection on a smooth surface.

If a light ray is incident on a reflective surface along the normal. The angle of incidence will be at 90 degrees which will be perpendicular to the surface of the mirror, the reflected ray will bounce back likewise at the same angle which will be perpendicular to the reflective surface.

Both the incident ray and the reflected ray and the normal will be parallel to each other.

4 0

3 years ago