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mote1985 [20]
4 years ago
12

Which element has the greatest average atomic mass? A. iodine B. bromine C. tellurium D. krypton

Chemistry
1 answer:
Jet001 [13]4 years ago
5 0
The Greatest Atomic Mass Out Of These Elements Is A Iodine
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Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is require
pishuonlain [190]
M₁ *V₁ = M₂ * V₂

12.0 * V₁ = 6.0 * 500.0

12.0 V₁ = 3000

V₁ = 3000 / 12.0

V₁ = 250 mL

hope this helps!
6 0
3 years ago
Read 2 more answers
How many moles are in 425.0 g of sodium chloride?
Airida [17]

About 7.272 moles. Hope this helps!

5 0
4 years ago
As a chlorine atom becomes a negative ion, the atom
Sav [38]

Answer : The correct option is, (1) Gains an electron and its radius increases.

Explanation :

The given element is chlorine.

Atomic number of chlorine = '17'

The electronic configuration of chlorine is, 1s^22s^22p^63s^23p^5

Number of electrons = 17

Number of protons = 17

The electronic configuration of chloride ion is, 1s^22s^22p^63s^23p^6

Number of electrons = 18

Number of protons = 17

When the chlorine atom gains an electron to acquire a stable electronic configuration. As the electrons add in the valence shell of the chlorine, the number of electrons increases but the number of protons remains the same. So, the protons will not be able to bind the extra electron and it will remain far from the nucleus.

6 0
4 years ago
Read 2 more answers
What is the pH of a solution with (H3O+)=5.6x10-2M?
balu736 [363]

Answer:

Explanation:

Given parameters:

Concentration of H₃O⁺  = 5.6 x 10⁻²M

Solution:

To solve for the concentration of H₃O⁺ in the solution, we simply use the expression below:

            pH = -log₁₀[H₃O⁺]

where [H₃O⁺] =  5.6 x 10⁻²M is the concentration of H₃O⁺

            pH = -log₁₀[5.6 x 10⁻²] = - x -1.25 = 1.25

3 0
3 years ago
Read 2 more answers
A solution is prepared by dissolving 0.26 mol of hydrazoic acid and 0.26 mol of sodium azide in water sufficient to yield 1.00 L
Pavel [41]

Answer:

The pH does not decrease drastically because the HCl reacts with the <u>sodium azide (NaN₃)</u> present in the buffer solution.

Explanation:

The buffer solution is formed by 0.26 moles of the weak acid, hydrazoic acid (HN₃), and by 0.26 moles of sodium azide (NaN₃). The equilibrium reaction of this buffer solution is the following:

HN₃(aq) + H₂O(l)  ⇄ N₃⁻(aq) + H₃O⁺(aq)          

The pH of this solution is:

pH = pka + log(\frac{[N_{3}^{-}]}{[HN_{3}]}) = -log(2.5 \cdot 10^{-5}) + log(\frac{0.26 mol/1 L}{0.26 mol/1 L}) = 4.60

When 0.05 moles of HCl is added to the buffer solution, the following reaction takes place:

H₃O⁺(aq) + N₃⁻(aq)  ⇄  HN₃(aq) + H₂O(l)

The number of moles of NaN₃ after the reaction with HCl is:

\eta_{NaN_{3}} = \eta_{i} - \eta_{HCl} = 0.26 moles - 0.05 moles = 0.21 moles

Now, the number of moles of HN₃ is:

\eta_{HN_{3}} = \eta_{i} + \eta_{HCl} = 0.26 moles + 0.05 moles = 0.31 moles

Then, the pH of the buffer solution after the addition of HCl is:

pH = pka + log(\frac{[N_{3}^{-}]}{[HN_{3}]}) = -log(2.5 \cdot 10^{-5}) + log(\frac{0.21 mol/V_{T}}{0.31 mol/V_{T}}) = 4.43

The pH of the buffer solution does not decrease drastically, it is 4.60 before the addition of HCl and 4.43 after the addition of HCl.    

Therefore, the pH does not decrease drastically because the HCl reacts with the sodium azide (NaN₃) present in the buffer solution.

I hope it helps you!

6 0
3 years ago
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