Answer:
Use the activity formula,
T1/2 = 4.468 x 10^9 yr x 365 x 24 x 3600 = 1.409 x 10^17 sec
l = ln(2)/T1/2 = ln(2)/1.409 x 10^17 = 4.91932697 x 10^-18 s-1
DN/Dt = lN, 265 = 4.91932697 x 10^-18 x N
<u><em>N = 5.38 x 10^19 nuclei</em></u>
Answer:
b) The molecule has a molecular weight under 200 g/mole
Explanation:
The molecule has a molecular weight under 200 g/mole is the primary requirement for a molecule to be analyzed by Gas Chromatography.
Answer:
Reactants, the top would be activation energy, the bottom is energy released by reaction, products
Explanation:
Answer:
<em>P1V1</em><em>/</em><em>(</em><em>c1</em><em>+</em><em>2</em><em>3</em><em>7</em><em>)</em><em>=</em><em>P2V2</em><em>/</em><em>(</em><em>c2</em><em>+</em><em>2</em><em>3</em><em>7</em><em>)</em><em> </em><em>where </em><em>c</em><em>=</em><em>Celsius</em>
Explanation:
kelvin scale is alot covinent because of it absolute zero
