Question

Pleeeeeeeeeease

Answer 1

Answer:

The final equation is $y = \frac{4}{3}x - \frac{16}{3}$

Step-by-step explanation:

The slope of the line CB where, C(0,3) and B(12,-6) will be  

$M = \frac{- 6 - 3}{12 - 0} = - \frac{3}{4}$

Now, if the line perpendicular to the line CB has slope N, then M × N = - 1

⇒ $N = \frac{4}{3}$ {Since $M = - \frac{3}{4}$}

Now, equation of the straight lines which are perpendicular to CB will be in slope-intercept form  

$y = \frac{4}{3}x + c$ {Where, c is the y-intercept}

If this straight line passes through the point (7,4), then  

$4 = \frac{4}{3} \times 7 + c$

⇒ 12 = 28 + 3c

⇒ 3c = - 16

⇒ $c = - \frac{16}{3}$

Therefore, the final equation is $y = \frac{4}{3}x - \frac{16}{3}$ (Answer)