Answer:
Step-by-step explanation:
NA = √[(- 4 - 1 )² + (- 3 - 2)²] = 5√2
AT = √[(8 - 1 )² + (1 - 2)²] = 5√2
TS = √[(3 - 8 )² + (- 4 - 1)²] = 5√2
NS = √[(- 4 - 3 )² + (- 3 + 4)²] = 5√2
NA = AT = TS = NS = 5√2
= (- 3 - 2) / (- 4 - 1) = 1 ........ <em>(1)</em>
= (- 4 - 1) / (3 - 8 ) = 1 ......... <em>(2)</em>
From (1) and (2) ⇒ NA║TS
= ( 1 - 2) / ( 8 - 1) = - 1 / 7 .......... <em>(3)</em>
= ( - 4 + 3) / ( 3 + 4) = - 1 / 7 .... <em>(4)</em>
From (3) and (4) ⇒ AT║NS
Thus, NATS is rhombus.
He made his mistake in Step 2. Tom should have subtracted 4/8 instead of 1/8. The mistake is that he was not consistent when he multiplied Denominators (bottom number) must be the same when handling fractions so Tom must multiply both the numerator and denominator by the SAME number to balance it out. 1/2 x 4/4= 4/8. Subtract. 7/8 - 4/8= 3/8. Tom has 3/8 of a gallon of paint leftover.
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Answer:
(10^11)/3
10^6 x 10^5 = 10^11
8/5 x 5/24 = 1/3
so multiply 10^11 and 1/3 together
Answer:
<h2>
204π units²</h2>
Step-by-step explanation:
The lateral area of the cylinder includes both the side and the ends.
The area of the side can be found by calculating the circumference of the cylinder and multiplying that by the height: A = 2π(6 units )(11 units) = 132π units².
The area of one end of this cylinder can be found by applying the "area of a circle" formula: A = πr². Here, with r = 6 units, A = π(6 units)² = 36π units². Since the cylinder has two ends, the total area of the ends is thus 2(36π units) = 72π units.
The total lateral area of the cylinder is thus 72π units² + 132π units², or 204π units²
