H(t) = −16t^2 + 75t + 25
g(t) = 5 + 5.2t
A)
At 2, h(t) = 111, g(t) = 15.4
At 3, h(t) = 106, g(t) = 20.6
At 4, h(t) = 69, g(t) = 25.8
At 5, h(t) = 0, g(t) = 31
The heights of both functions would have been the closest value to each other after 4 seconds, but before 5 seconds. This is when g(x) is near 30 (26-31), and the only interval that h(t) could be near 30 is between 4 and 5 seconds (as it is decreasing from 69-0).
B) The solution to the two functions is between 4 and 5 seconds, as that is when their height is the same for both g(t) and h(t). Actually the height is at 4.63 seconds, their heights are both
What this actually means is that this time and height is when the balls could collide; or they would have hit each other, given the same 3-dimensional (z-axis) coordinate in reality.
Since <em>N</em>/2 leaves a remainder, <em>N</em> must be odd and ends with 1, 3, 5, 7, or 9.
<em>N</em>/5 also leaves a remainder, so <em>N</em> is not divisible by 5, so it does not end in 5.
The only correct choice is then 9, since
1 = 0•5 + 1 and 1 = 0•2 + 1
3 = 0•5 + 3 and 3 = 1•2 + 1
7 = 1•5 + 2 and 7 = 3•2 + 1
9 = 1•5 + <u>4</u> and 9 = 4•2 + <u>1</u>
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Alternatively, the given information is equivalent to saying
Then you can use the Chinese remainder theorem to find <em>N</em>.
Answer:
44
Step-by-step explanation:
Answer:
YES
Step-by-step explanation:
The length of the repel line using one of the 3 trigonometry ratios will be 186.78 feet.
<h3>How to calculate the length?</h3>
From the information given, Peyton is walking her dog, Willow, on a local trail and the dog falls 153 feet down a ravine.
The length will be calculated thus:
Cos 35° = 153/AC.
AC = 153/cos 35°
AC = 153/0.819
AC = 186.78 feet.
Therefore, the length is 186.78 feet.
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