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2 years ago

A flowerbed has an area of 12 square meters. What is the largest possible perimeter of the flowerbed?

Mathematics

1 answer:

grandymaker [24]2 years ago

3 0

Answer:

5 feet long and 1 foot wide, and vise versa.

Step-by-step explanation:

First of all, we can make pairs.

Then just look at what I do

(6, 0) <= This can't be possible

(5, 1) <= This is the largest

(4, 2) <= This isn't the largest

(3, 3) <= This isn't the largest

(2, 4) <= This isn't the largest

(1, 5) <= This is the largest

(0, 6) <= This can't be possible

The ones labled "This is the largest" are the correct ones

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Solve for x (2x-8) (9x-10)

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Answer

x+3=17

Step-by-step explanation:

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3 years ago

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Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz

Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The vertical component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the horizontal.

By resolving Jason's force of pull in the horizontal direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11

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2 years ago

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Find the value of 1225 by using prime factorization

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3 years ago

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Jackson bought 5 ounces of raisins for $4, how many ounces cna he buy for $1.

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He can buy 1 1\4 ounce for a dollar or 1.25 ounces or depending on your answer choice 1 ounce. All those answer are right

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3 years ago

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Graph the system & write its solution 2x+y=-4 Y=-1/2x-1

xz_007 [3.2K]

Answer:

The solution of system of equation is (-2,0)

Step-by-step explanation:

Given system of equation are

Equation 1 : 2x+y=(-4)

Equation 2 : y+ $\frac{1}{2}$ x=(-1)

To plot the equation of line, we need at least two points

For Equation 1 : 2x+y=(-4)

Let x=0

2x+y=(-4)

2(0)+y=(-4)

y=(-4)

Let x=1

2x+y=(-4)

2(1)+y=(-4)

y=(-6)

Therefore,

The required points for equation is (0,-4) and (1,-6)

For Equation 2 : y+ $\frac{1}{2}$ x=(-1)

Let x=0

y+ $\frac{1}{2}$ x=(-1)

y+ $\frac{1}{2}$ (0)=(-1)

y=(-1)

Let x=2

y+ $\frac{1}{2}$ x=(-1)

y+ $\frac{1}{2}$ (2)=(-1)

y=(-2)

The required points for equation is (0,-1) and (2,-2)

Now, plot the graph using this points

From the graph,

The red line is equation 1 and blue line is equation 2

Since. The point of intersection is solution of system of equations

The solution of system of equation is (-2,0)

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3 years ago