What is the quotient of 36,772 and 58 type your answer as a number

Mathematics

1 answer:

julia-pushkina [17]3 years ago

8 0

The answer is 634.

Have a nice day!

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Davis printed 24 photos in 8 minutes. how many photos did he print per minute

Arada [10]

24 photos in 8 minutes

24/8 = the number of photos per minute

24/8 = 3

3/1 is the number of photos/ minutes

3 photos per minute is your answer

hope this helps

8 0

3 years ago

Read 2 more answers

How Do You Write .0676767 In Scientific Notation?

evablogger [386]

6.8 x 10^-2

The scientific notation of 70, 030, 000. To find the scientific notation of this value 
1. We first move the period which separates the whole number from the decimal number which is located after the numbers of the given value.
2. We move it in the very recent order number which is seventy million, seven and zero. 
3. It becomes 7.003
4. Thus we count how many moves we did from the tens to the ten million order place. 
5. 7.003 x 10^7

4 0

3 years ago

Thank you very much for your help!

Kobotan [32]

For a.
$x^2+y^2=25$

For b.
$(x-4)^2+(y-3)^2=25$

For c.
$(x-5)^2+(y-4)^2=9$

Hope that helps

5 0

3 years ago

. Given that O is the centre of the following circle, find the values of the unknowns.

alex41 [277]

Given:

Radius of circle is 13 cm

Height of triangle is 5 cm

To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

$a^{2} + 5^{2} = 13^{2}$

$a^{2} + 25 = 169$

$a^{2} = 169 - 25$

$a^{2} = 144$

$\sqrt{a^{2}}=\sqrt{144}$

$a = 12$

Now to find the value of 'b', i will use law of cosine,

$c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }$

$12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta = 0.3846\\\beta = cos^{-1}(0.3846)\\\beta = 67.38$