To find the maximum height you need to find the vertex:(h,k) Your equation is in vertex form a(x-h)+k and the vertex is (h,k) where k is the maximum height and the h is the distance it went to reach the maximum height. k=6 so the kangaroo's maximum height is 6 feet.
To find how long is the kangaroo's jump, take a look at the graph. You will notice that the parabola ends at the distance the kangaroo jumped. You will also see that it is the one of the x-intercepts.
-.03(x-14)^2+6=0 -.03(x-14)^2+6-6=0-6 -.03(x-14)^2=-6 -.03/-.03(x-14)=-6/-.03 (x-14)^2=200 [(x-14)^2]^.5=200^.5 x-14=(200)^.5 x-14+14=(200)^.5+14 x≈28.14 feet The kangaroo jumped a distance of 28.14 feet.
You will notice that the square root of a number gives you two solutions a positive and a negative one. The other solution is -.14, which we know distance is not negative so we do not use that solution. Also, I used the ^.5 instead of using the square root. It is the same.
