Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
Assuming "the speaker takes up 1/6 of the internal volume"
volume is 9³ in³
you want the remaining volume, which is 5/6 of the total
(5/6)9³ = 607.5 in³
double that if you want the remaining volume for BOTH speakers....
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Answer:
First do the case in which none of the digits is 0.
There are 9 ways to choose the digit that repeats 3 times and 8 ways to pick the other, after this there are 4 ways to order the digits. So 9×8×4.
Now we look at the cases in which the digit 0 repeats 3 times. Clearly the 9 numbers are 1000,2000,3000,…,9000.
Lastly we look at the cases in which 0 appears once. There are 9 ways to pick the other digit and 3 ways to order.
So the final answer is 9×8×4+9+9×3.
Answer: Don’t give any personal information out lol
Step-by-step explanation:
