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nexus9112 [7]
3 years ago
6

You placed each of these cards in a brown paper bag and randomly select one and then record your results. After each selection,

you place it back in the bag and select another. You do this for a total of 50 times and your results are: 6 times you picked the ace, 14 times you picked the 2, 13 times you picked the 3, 4 times you picked the 4, and 13 times you picked the 5. After looking at your results, what is the experimental probability of selecting the 4? Hint: You may have to reduce. *
Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:

The experimenta probability of picking a 4 is \frac{4}{50}

Step-by-step explanation:

To determine the experimental probability, we just need to divide the number of observations of the specific event by the total number of trials. In this case, we are interested in the event "picking a 4 card". This event happened 4 times. We have a total number of trials of 50. So , the experimental probability is

\frac{4}{50}

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Answer:

\text{d.}\quad a_n=-2.25(2)^{n-1}

Step-by-step explanation:

The common ratio is given as 2, so the base of any exponential must be 2 (not -2 or 2.25). The 4th term is negative, so the initial value must be negative (since the multiplying factor is positive). The only selection matching these requirements is d.

You know the general term is ...

... an = a1·r^(n-1)

so the 4th term is

... -18 = a1·2^(4-1) = 8·a1

Then the first term is ...

... a1 = -18/8 = -2.25 . . . . . confirms our choice of answer d.

7 0
3 years ago
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Answer:

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Step-by-step explanation:

7 0
3 years ago
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lisov135 [29]
Alrighty
remember
log_a(b)=c means a^c=b
and
ln(x)=log_e(x)
and
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log_e(x^2+4x-5)=0 means
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7 0
3 years ago
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Degger [83]
<h3>Answer:</h3>

Mean: 17.2

Median: 18

Mode: 18

<h3>Solution:</h3>

Mean: The sum of all observation divided by several observation

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Median:it is the middlemost observation of data arraged in increasing or decreasing order of values

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Mode:it is the value that occurs frequently in a set of data

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Answer:

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Step-by-step explanation:

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