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Nataly [62]
3 years ago
14

Pls help me add me on ig hairstyles2530

Mathematics
2 answers:
Anit [1.1K]3 years ago
6 0

Answer:

Step-by-step explanation:

Strike441 [17]3 years ago
6 0
If the given lengths of 7cm, 24cm, and 25cm for the sides of a triangle satisfy the equation of the Pythagorean theorem then yes!
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Pls help me giving brainless.​
Drupady [299]

Answer: about 8 dollars

Step-by-step explanation:

2*12=24

8*12=96

12*12=144

8 0
3 years ago
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a coin purse contains 3 quarters, 2 dimes, 1 nickle, and 4 pennies. what is the probability of selecting a nickle, then a dime w
mixer [17]

Answer:

.0222

The probability of selecting a nickle then a dime without replacement is 2.22%.

(1/10)*(2/9)= .0222

5 0
3 years ago
Help find the volume.
Mrac [35]
The answer you are looking for is 324
6 0
4 years ago
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A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ
Over [174]

Answer: The correct number of balls is (b) 4.

Step-by-step explanation:  Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

^{10}C_r=210.

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10

If r = 2, then

^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45

If r = 3, then

^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120

If r = 4, then

^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.

Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

4 0
3 years ago
Read 2 more answers
Please help me solve.
Bingel [31]

Answer:

Consultant B :)

Step-by-step explanation:

6 0
4 years ago
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