Answer:
Explanation:
mass of displaced oil = 11 x .9
= 9.9 gm
9.9 x 10⁻³ kg
weight of displaced oil = 9.9 x 9.81 x 10⁻³ N
= .097 N .
buoyant force by oil = .097 N
weight of unknown metal = .1 x 9.8
= .98 N .
weight of metal in oil = .98 - .097
= .883 N .
=
Before the launch, the momentum of the (spacecraft + asteroid) was zero. So after the launch, the momentum of the (spacecraft + asteroid) has to be zero.
Momentum = (mass) x (velocity)
Momentum after the launch:
Spacecraft: (1,000 kg) x (250 m/s) = 250,000 kg-m/s
Asteroid: (mass) x (-25 m/s)
Their sum: 250,000 - 25(mass) .
Their sum must be zero, so 250,000 kg-m/s = (25 m/s) x (mass)
Divide each side by 25 : 10,000 kg-m/s = (1 m/s) x (mass)
Divide each side by (1 m/s) : 10,000 kg = mass
Answer:
E. d and O
Explanation:
"Light passing through a single slit forms a diffraction pattern somewhat different from those formed by double slits or diffraction gratings".
According to Huygens’s principle, "for each element of the wavefront in the slit emits wavelets. These are like rays that start out in phase and head in all directions. (Each ray is perpendicular to the wavefront of a wavelet.) Assuming the screen is very far away compared with the size of the slit, rays heading toward a common destination are nearly parallel".
The destructive interference for a single slit is given by:

Where
d is the slit width
is the light's wavelength
is the angle relative to the original direction of the light
m is the order od the minimum
I represent the intensity
When the intensity and the wavelength are incident normally the angular as we can see on the expression above the angular separation just depends of the distance d and the wavelength O.
Answer:
Resistivity, electrical resistance of a conductor of unit cross-sectional area and unit length.
Explanation:
A characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors.
Answer:
0.22 m
Explanation:
m = 0.43 kg, K = 561 N/m
Vmax = 8 m/s
Let the amplitude of the oscillations be A.
The formula for the angular frequency of oscillation sis given by


ω = 36.1 rad/s
The formula for the maximum velocity is given by
Vmax = ω x A
A = Vmax / ω
A = 8 / 36.1 = 0.22 m