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alexgriva [62]
3 years ago
7

What quantity does a Percent measure?

Physics
2 answers:
eimsori [14]3 years ago
3 0

In mathematics, a percentage is a number or ratio expressed as a fraction of 100.

harina [27]3 years ago
3 0

Answer:

In mathematics, a percentage (from Latin per centum "by a hundred") is a number or ratio expressed as a fraction of 100.

Explanation:

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9. In the sun devil football game, a receiver, who is standing still, has caught a pass from the quarterback. Before he can move
otez555 [7]

Answer:

The mass of the receiver is 68.862 kg

Explanation:

Given;

let mass of the receiver be "m₁"

initial velocity of the receiver, u₁ = 0

mass of the tackler, m₂ =  156 kg

initial velocity of the tackler, u₂ = 6.89 m/s

their final velocity, v = 4.78 m/s

Apply the principle of conservation of linear momentum, for inelastic collision;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(m₁ x 0) + (156 x 6.89) = 4.78(m₁ + 156)

0 + 1074.84 = 4.78 (m₁ + 156)

1074.84 = 4.78 (m₁ + 156)

m₁ + 156 = 1074.84 / 4.78

m₁ + 156 = 224.862

m₁ = 224.862 - 156

m₁ = 68.862 kg

Therefore, the mass of the receiver is 68.862 kg

5 0
3 years ago
A high school physics student is sitting in a seat read-
Nataly_w [17]

The equilibrium condition allows finding the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Newton's second law gives the relationship between force, mass and acceleration of bodies, in the special case that the acceleration is is zero equilibrium condition.

            ∑ F = 0

Where F is the external force.

The free body diagram is a diagram of the forces on bodies without the details of the shape of the body, in the attached we can see a diagram of the forces.

Let's analyze the force on the chair.

            N_{chair} - W_{chair} - W_{student} = 0 \\ \\N_{chair} = W_{chair} + W_{student}

Let's analyze the forces on the student.

          N_{student} - W_{student} = 0  \\N_{student} = W _{student}

           

In conclusion using the equilibrium condition we can find the result for the force that the chair exerts on the student is:

  • The reaction force that the chair exerts on the student's support is equal to the student's weight.

Learn more here: brainly.com/question/18117041

7 0
3 years ago
A point P is placed exactly between two charges, Q1 and Q2. If the electric field experienced by point P due to charge Q1 is 1.5
iren2701 [21]

<em>Answer:  D</em>

<em>Given data:</em>

The electric field due to charge q₁  is (E₁) = 1.5 × 10⁵ N/C

The electric field due to charge q₂ is (E₂) = 7.2 × 10⁵ N/C

Determine the net electric field at point P (Enet) = ?

electric field measured in Newtons/coulomb

<em>We know that,</em>

        The net electric field (Enet) is vector sum of E₁ and E₂ caused by the charge q₁ and q₂ respectively

             Enet = E₁ + E₂

                       = (1.5 × 10⁵)+ (7.2 × 10⁵)

                       = 8.7 × 10⁵ Newtons/coulomb

<em>The net electric field at point P is  8.7 × 10⁵ N/C</em>

4 0
3 years ago
Without Newton’s third law of motion, what would an object sitting on a table do?
Angelina_Jolie [31]

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

8 0
3 years ago
Read 2 more answers
An open bed truck is moving at 20 m/s and comes to a stop. A 100 kg crate sitting in the back of the truck remains at rest in th
zzz [600]

The work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

<h3>Work done by friction to prevent the crate from moving</h3>

The work done is determined by applying the principle of conservation of energy.

W = K.E

W = ¹/₂mv²

where;

  • m is mass of crate
  • v is speed of the crate with respect to the truck = 20 m/s

W = ¹/₂(100)(20²)

W = 20,000 J

Thus, the work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

Learn more about work done here: brainly.com/question/8119756

#SPJ1

3 0
2 years ago
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