F_P + F_Q = M g
F_P = M g - F_Q
Torque, or moment of force:
∑ M_P = 0
∑ M_P = M g L - F_Q · 3 L
0 = M g L - 3 F_Q L / : L
0 = M g - 3 F_Q
3 F_Q = M g
F_Q = M g /3
Finally:
F_P = M g - M g/3
F_P = 4 M g / 3
i assume it will be 5mins i hope thi shelp u out
F=ma
a=F/m
a=2000/1000
a=2 m/s^2
I would say B but I have no clue
Efficiency is completing a task as fast a possible the the least amount of effort.
