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Len [333]
3 years ago
12

A yo-yo is made from two uniform disks, each with mass m and radius R, connected by a light axle of radius b. A light, thin stri

ng is wound several times around the axle and then held stationary while the yo-yo is released from rest, dropping as the string unwinds. Find the linear acceleration and angular acceleration of the yo-yo and the tension in the string.
Physics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

linear acceleration

a = \frac{2g}{2 + \frac{R}{b}}

angular acceleration

\alpha = \frac{2g}{R(2 + \frac{R}{b})}

Explanation:

As we know that the force due to tension force is upwards while weight of the disc is downwards

so we will have

2mg - T = 2ma

also we have

Tb = (\frac{1}{2}mR^2 + \frac{1}{2}mR^2)\alpha

now we have

Tb = mR^2(\frac{a}{R})

T = \frac{mRa}{b}

now we have

2mg = (2ma + \frac{mRa}{b})

a(2 + \frac{R}{b}) = 2g

so we have

linear acceleration

a = \frac{2g}{2 + \frac{R}{b}}

angular acceleration

\alpha = \frac{2g}{R(2 + \frac{R}{b})}

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PLEASE HELP SEE PART 2 FOR MORE INFO
Angelina_Jolie [31]

Answer:

This question cannot be answered

Explanation:

This is a practical experiment which can only be done in person. Kindly go through the instructions and do the experiment carefully.

8 0
3 years ago
The length of second, s pendulum at a place where gravitational acceleration ]g] is 9.8 m/s
amm1812
O.99 m long .simple pendulum time period is 2s for second formula then use formula T=2pi.rt(lenght/gravity)
6 0
3 years ago
A car traveling at 28 m/s starts to decelerate steadily. It comes to a complete stop in 13 seconds. What is its acceleration?
Maru [420]

Acceleration = (change in speed) / (time for the change)

change in speed = (speed at the end) minus (speed at the beginning)

change in speed = (zero) minus (28 m/s) = -28 m/s

Acceleration = (-28 m/s) / (13 sec)

Acceleration = -2.15 m/s²

5 0
3 years ago
According to Bernoulli's equation, the pressure in a fluid will tend to decrease if its velocity increases. Assuming that a wind
Pie

Answer:

The pressure drop predicted by Bernoulli's equation for a wind speed of 5 m/s

= 16.125 Pa

Explanation:

The Bernoulli's equation is essentially a law of conservation of energy.

It describes the change in pressure in relation to the changes in kinetic (velocity changes) and potential (elevation changes) energies.

For this question, we assume that the elevation changes are negligible; so, the Bernoulli's equation is reduced to a pressure change term and a change in kinetic energy term.

We also assume that the initial velocity of wind is 0 m/s.

This calculation is presented in the attached images to this solution.

Using the initial conditions of 0.645 Pa pressure drop and a wind speed of 1 m/s, we first calculate the density of our fluid; air.

The density is obtained to be 1.29 kg/m³.

Then, the second part of the question requires us to calculate the pressure drop for a wind speed of 5 m/s.

We then use the same formula, plugging in all the parameters, to calculate the pressure drop to be 16.125 Pa.

Hope this Helps!!!

7 0
3 years ago
2. A person began running due east and covered 15 kilometers in 2.0 hours. What is the average velocity of the person?
Angelina_Jolie [31]

Answer:

7.5 km/h (2.1 m/s) due east

Explanation:

The average velocity of the person is given by:

v=\frac{d}{t}

where

d is the displacement

t is the time taken

In this problem,

d = 15 km is the displacement

t = 2.0 h is the time elapsed

so the average velocity is

v=\frac{15 km}{2.0 h}=7.5 km/h

and the direction is the same as the displacement (east).

We can also convert the velocity into SI units (m/s). We have:

d = 15 km = 15,000 m

t = 2.0 h * 3600 s/h = 7200 s

v=\frac{15,000 m}{7200 s}=2.1 m/s

4 0
3 years ago
Read 2 more answers
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