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Len [333]
3 years ago
12

A yo-yo is made from two uniform disks, each with mass m and radius R, connected by a light axle of radius b. A light, thin stri

ng is wound several times around the axle and then held stationary while the yo-yo is released from rest, dropping as the string unwinds. Find the linear acceleration and angular acceleration of the yo-yo and the tension in the string.
Physics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

linear acceleration

a = \frac{2g}{2 + \frac{R}{b}}

angular acceleration

\alpha = \frac{2g}{R(2 + \frac{R}{b})}

Explanation:

As we know that the force due to tension force is upwards while weight of the disc is downwards

so we will have

2mg - T = 2ma

also we have

Tb = (\frac{1}{2}mR^2 + \frac{1}{2}mR^2)\alpha

now we have

Tb = mR^2(\frac{a}{R})

T = \frac{mRa}{b}

now we have

2mg = (2ma + \frac{mRa}{b})

a(2 + \frac{R}{b}) = 2g

so we have

linear acceleration

a = \frac{2g}{2 + \frac{R}{b}}

angular acceleration

\alpha = \frac{2g}{R(2 + \frac{R}{b})}

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Please find the answer in the explanation

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Describe the quantum mechanical model of the atom and several observations which support this model.
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Three point charges are located on the x-axis. The first charge, q1 = 10 μC, is at x = -1.0 m. The second charge, q2 = 20 μC, is
victus00 [196]

Answer:

<em>3.15 N towards the positive x-axis</em>

<em></em>

Explanation:

first charge has charge q1 = 10 μC = 10 x 10^-6 C

second charge has charge q2 = 20 μC = 20 x 10^-6 C

third charge has charge q3 = -30 μC = -30 x 20^-6 C

According to coulomb's law, force between two charged particle is given as

F = \frac{-kQq}{r^2}

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F is the force between the charges

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Q is the magnitude of one charge

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is the distance between these two charges

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distance r between them = 0 - (-1.0) = 1 m

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distance between them = 2.0 - 0 = 2 m

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Resultant force on q2 = 1.8 N + 1.35 N = <em>3.15 N towards the positive x-axis</em>

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