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Len [333]
3 years ago
12

A yo-yo is made from two uniform disks, each with mass m and radius R, connected by a light axle of radius b. A light, thin stri

ng is wound several times around the axle and then held stationary while the yo-yo is released from rest, dropping as the string unwinds. Find the linear acceleration and angular acceleration of the yo-yo and the tension in the string.
Physics
1 answer:
schepotkina [342]3 years ago
4 0

Answer:

linear acceleration

a = \frac{2g}{2 + \frac{R}{b}}

angular acceleration

\alpha = \frac{2g}{R(2 + \frac{R}{b})}

Explanation:

As we know that the force due to tension force is upwards while weight of the disc is downwards

so we will have

2mg - T = 2ma

also we have

Tb = (\frac{1}{2}mR^2 + \frac{1}{2}mR^2)\alpha

now we have

Tb = mR^2(\frac{a}{R})

T = \frac{mRa}{b}

now we have

2mg = (2ma + \frac{mRa}{b})

a(2 + \frac{R}{b}) = 2g

so we have

linear acceleration

a = \frac{2g}{2 + \frac{R}{b}}

angular acceleration

\alpha = \frac{2g}{R(2 + \frac{R}{b})}

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t₁= 5.1 years

C ) Given t = 10 years , t₁ = ? v = .8c

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t₁= 16.7  years

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\frac{10}{\sqrt{1-\frac{.16c^2}{c^2} } }

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The velocity of a satellite describing a circular orbit is<u> constant</u> and defined by the following expression:  

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R=r_{Earth}+h=8080000m the radius of the orbit (measured from the center of the planet to the satellite).  

This means the radius of the orbit is equal to <u>the sum</u> of the average radius of the Earth r_{Earth} and the altitude of the satellite above the Earth's surface h.

Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. It depends on the mass of the massive body (the Earth).

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