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3 years ago

Please I need help With this question thank you for your help me

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

Using CPCTC we can derive that WM = 8 and OL = 10.

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PLEASE ANSWER ASAP *picture attached*<br>f(x) = x2 + 1 g(x) = 5 – x

Eva8 [605]

Answer:

$x^{2} +x-4$

Step-by-step explanation:

To get the answer just subtract f(x) by g(x)

The work is shown below:

$(f-g)(x)= f(x)-g(x)\\\\(f-g)(x)= (x^{2} +1)-(5-x)\\\\(f-g)(x)= x^{2} +1-5+x\\\\(f-g)(x)= x^{2} -4+x\\\\(f-g)(x)= x^{2} +x-4\\\\$

7 0

2 years ago

2. Find the next three terms of the sequence.

Fudgin [204]

Answer:

The correct answer is D. -2,592, -15,552, -93,312

Step-by-step explanation:

Each of the terms is the previous term multiplied by 6. You can find this by taking any term and dividing it by the one before it. The answer will always be 6.

-72/-12 = 6

-12/-2 = 6

So, in order to find the next 3, we take the last term and multiply it by 6.

-432 * 6 = -2,592

-2,592 * 6 = -15,552

-15,552 * 6 = -93,312

4 0

3 years ago

An electrician charges $40 per visit, and $20 per hour of work. On a particular day, he made 3 visits and calculated that his av

saw5 [17]

Answer:

4 hours

Step-by-step explanation:

For three visits, the electrician earned $40 × 3 = $120 in "per-visit" charges. For working x hours, he earned 20x in "per-hour" charges. The total of these came to 50x:

120 +20x = 50x

120 = 30x . . . . . . . . subtract 20x

4 = x . . . . . . . . . . . . . divide by 30

The electrician worked 4 hours that day.

3 0

3 years ago

in the lunch room there were 100 chocolate milk cartons at lunch when lunch was over 88 had been purchased

ratelena [41]

Answer:

12 left over 100-88=12

7 0

2 years ago

Caden states that n^2 +3n + 2n is an equivalent expression to 6n. Why is Caden's statement incorrect?

malfutka [58]

$\begin{gathered} \text{The simplification of n}^2+3n+2n\text{ is:} \\ i)n^2+5n \\ By\text{ collecting common term, this can be written in form of:} \\ ii)\text{ n(n+5)} \end{gathered}$

Thus, options A and D hold, from the simplifications above.

Let's consider the validity of the remaining options provided.

$\begin{gathered} \text{For option B)} \\ \text{substitute for n=1 into the expression n}^2+3n+2n,\text{ we have} \\ 1^2+3(1)+2(1)=1+3+2=6 \\ \text{substitute for n=1 into the expression 6n, we have} \\ 6(1)=6 \\ \text{Thus, the expression n}^2+3n+2n\text{ is equivalent to 6n, for n=1} \end{gathered}$ $\begin{gathered} \text{For option C)} \\ \text{The expression n}^2+3n+2n\text{ does not simplify to 7n} \end{gathered}$ $\begin{gathered} \text{For option E)} \\ \text{substitute for n=4 into the expression n}^2+3n+2n,\text{ we have:} \\ 4^2+3(4)+2(4)=16+12+8=36 \\ \text{substitute for n=6 into the expression 6n, we have:} \\ 6(4)=24 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=4} \end{gathered}$ $\begin{gathered} \text{For option F)} \\ \text{substitute for n=3 into the expression n}^2+3n+2n,\text{ we have:} \\ 3^2+3(3)+2(3)=9+9+6=24 \\ \text{substitute for n=3 into the expression 6n, we have:} \\ 6(3)=18 \\ \text{Thus, the two(2) expressions are not equivalent to each other, for n=3} \end{gathered}$

Hence, the correct options that apply are options A, D, E and F

7 0

11 months ago