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pychu [463]
4 years ago
9

Which is the correct expansion of the term Internet? 

Computers and Technology
2 answers:
kirill115 [55]4 years ago
8 0

Answer:

international network

Explanation:

dezoksy [38]4 years ago
8 0

Answer:

Internetwork is the correct  choice for Plato

Explanation: took the test

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Assume you are given a boolean variable named isNegative and a 2-dimensional array of ints that has been created and assigned to
Anon25 [30]

Answer:

#include <iostream>

using namespace std;

int main(){

   int rows, cols;

   bool isNegatives;

   cout<<"Rows: ";

   cin>>rows;

   cout<<"Columns: ";

   cin>>cols;

   int a2d[rows][cols];

   for(int i =0;i<rows;i++){

   for(int j =0;j<cols;j++){

       cin>>a2d[i][j];}    }

   int negatives, others = 0;

   for(int i =0;i<rows;i++){

   for(int j =0;j<cols;j++){

       if(a2d[i][j]<0){

           negatives++;}

       else{

           others++;}}    }

   if(negatives>others){

       isNegatives = true;}

   else{

       isNegatives = false;}

   cout<<isNegatives;  

   return 0;

}

Explanation:

For clarity and better understanding of the question, I answered the question from the scratch.

This line declares number of rows and columns

   int rows, cols;

This line declares the Boolean variable

   bool isNegatives;

This line prompts user for rows

   cout<<"Rows: ";

This line gets the number of rows

   cin>>rows;

This line prompts user for columns

   cout<<"Columns: ";

This line gets the number of columns

   cin>>cols;

This line declares the array

   int a2d[rows][cols];

This line gets user input for the array

<em>    for(int i =0;i<rows;i++){</em>

<em>    for(int j =0;j<cols;j++){</em>

<em>        cin>>a2d[i][j];}    }</em>

This line declares and initializes number of negative and others to 0

   int negatives, others = 0;

The following iteration counts the number of negatives and also count the number of non negative (i.e. others)

<em>    for(int i =0;i<rows;i++){</em>

<em>    for(int j =0;j<cols;j++){</em>

<em>        if(a2d[i][j]<0){</em>

<em>            negatives++;}</em>

<em>        else{</em>

<em>            others++;}}    }</em>

This checks of number of negatives is greater than others

   if(negatives>others){

If yes, it assigns true to isNegatives

       isNegatives = true;}

   else{

If otherwise, it assigns false to isNegatives

       isNegatives = false;}

This prints the value of isNegatives

   cout<<isNegatives;  

<em>See attachment</em>

Download cpp
5 0
3 years ago
Explain ,how the computer network reduces cost of operation? (don't copy from any website)​
melomori [17]

Answer:

Computer network reduces the operation cost as it allows to share software and hardware in the network.

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3 years ago
You have to calculate the total amount you spent at the mall today. Which function should you use to do so?
rosijanka [135]
If it has to be exactly then C-sum
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A variable that can be modified from anywhere within a program is called a?
larisa86 [58]
A - a global variable
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Simplest way to start baking career is to attend_______.<br><br><br><br>​
ivolga24 [154]
...attend course
I hope my answer helps.
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