Answer:
what is the question and answers?
Answer:
full/incremental backup
Explanation:
I believe it's full/incremental backup.
Answer:
import java.util.Scanner;
public class num10 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the numbers to add up. enter 999 to stop");
int num = in.nextInt();
int sum = 0;
while (num!=999){
sum = sum+num;
System.out.println("Enter the next number");
num = in.nextInt();
}
System.out.println("The sum is: "+sum);
}
}
Explanation:
The application is implemented in Java
A while loop is used to continously prompt user for inputs. The condition of the while loop is while (num!=999)
When the number 999 is entered, it displays the sum which is initialized to 0
Answer:
If two network adapters on the same network transmit at the same time, one of the adapters would stop transmitting until the second adapter has finished transmitting before retransmission
Explanation:
Carrier Sense Multiple Access with Collision Detection (CSMA/CD) is a network protocol used to prevent data collision. CSMA/CD detects collisions by sensing transmissions from other nodes. If a collision is detected, the node stops transmitting, sends a jam signal, and then waits for some time until the channel is idle before retransmission.
If two nodes on the network start transmitting at the same time, the nodes will detect the collision and take the appropriate action.
If two network adapters on the same network transmit at the same time, one of the adapters would stop transmitting until the second adapter has finished transmitting before retransmission
Hi, you haven't provided the programing language, therefore, we will use python but you can extend it to any programing language by reading the code and the explanation.
Answer:
n1 = int(input("First numeber: "))
n2 = int(input("Second numeber: "))
for i in range(5):
r1 = n1%10
r2 = n2%10
print(r1+r2)
n1 = n1//10
n2 = n2//10
Explanation:
- First, we ask for the user input n1 and n2
- We create a for-loop to calculate the sum of each place-value of two numbers
- We obtain the last number in n1 by using the mod operator (%) an the number ten this way we can always take the last value, we make the same for n2
- Then we print the result of adding the last two numbers (place value)
- Finally, we get rid of the last value and overwrite n1 and n2 to continue with the process
