What is the range of h (x)

1 answer:

6 0

The range of the function is the set of all possible outputs, that is, the set of all values obtained by applying the function to elements of the domain. So the set of all values which can be obtained by applying h(x) to an element of its domain is {−4,0,5,60} , and thus that is the range of h(x) .

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NNADVOKAT [17]

Answer:

the length = eleven meters.

Step-by-step explanation:

area divided by width.

33/3 = 11.

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2 years ago

Number 49....I need help

sergiy2304 [10]

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now, also let's keep in mind that, when the car was driven for 200 miles, that's 200/25 or 8 25mile intervals, so the 25mile charge kicked in 8 times.

$\bf \stackrel{cost}{y}=\stackrel{fixed~charge}{F}+\stackrel{25mile~intervals}{m}\quad \stackrel{25mile~charge}{x}\implies y=F+mx\\\\
-------------------------------\\\\
\begin{cases}
200=F+2x\implies 200-2x=\boxed{F}\\
245=F+8x\\
----------\\
245=\boxed{200-2x}+8x
\end{cases}
\\\\\\
45=6x\implies \cfrac{45}{6}=x\implies \cfrac{15}{2}=x\impliedby 
\begin{array}{llll}
\textit{so the 25mile charge is}\\
\textit{7 bucks and 50cents}
\end{array}
\\\\\\
$

$\bf 200=F+2\left( \frac{15}{2} \right)\implies 200=F+15\implies 185=F
\\\\\\
\textit{and the \underline{fixed charge} is 185 bucks then, let's check for 450}
\\\\\\
\boxed{y=185+\frac{15}{2}x}\qquad 
\begin{cases}
450~miles\\\\
\cfrac{450}{25}\implies 18~\textit{\underline{25mile intervals}}\\\\
x=18
\end{cases}
\\\\\\
y=185+\cfrac{15}{2}\cdot 18\implies y=185+135\implies y=320$

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Go to your graph , and make a straight line . A linear function is basically a line , so make a line to those numbers in the graph .

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Sav [38]

Hello,

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Hope this helps

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