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zhenek [66]
3 years ago
15

Express each fraction or mixed number as a percent

Mathematics
1 answer:
vladimir1956 [14]3 years ago
3 0
So,

#1: \frac{5}{8}

We know that \frac{1}{8} = 0.125, or 12.5%.
Therefore, we just have to multiply 12.5% by 5 to get \frac{5}{8}  in percent form.

12.5(5) = 62.5

\frac{5}{8}  as a percent is 62.5%.


#2: 2  \frac{4}{7}

2 \frac{4}{7} = 200% + \frac{4}{7}

4/7 rounded to the nearest thousandth is 0.5714, or 57.14%.

200% + 57.14% = 257.14%
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Step-by-step explanation:

Midpoint = (x1 + x2 ÷ 2) , (y1 + y2 ÷ 2)

MP= (7 + 3 ÷ 2), (-5 + 3 ÷ 2)

= (10÷2), (-2÷2)

=(5), (-1)

MP= (5, -1)

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In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60
Olegator [25]

Answer:

7.38-1.96\frac{2.51}{\sqrt{601}}=7.18    

7.38+1.96\frac{2.51}{\sqrt{601}}=7.58    

For this case the confidence interval is given by :

7.18 \leq \mu \leq 7.58

Step-by-step explanation:

Data provided

\bar X=7.38 represent the sample mean for the fuel efficiencies

\mu population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size  

Confidence interval

The formula for the confidence interval of the true mean is given by:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom for this case is given by:

df=n-1=601-1=600

The Confidence level for this case is 0.95 or 95%, and the significance level \alpha=0.05 and \alpha/2 =0.025 and the critical value is given by t_{\alpha/2}=1.96

Replcing into the formula for the confidence interval is given by:

7.38-1.96\frac{2.51}{\sqrt{601}}=7.18    

7.38+1.96\frac{2.51}{\sqrt{601}}=7.58    

For this case the confidence interval is given by :

7.18 \leq \mu \leq 7.58

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