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zhenek [66]
2 years ago
15

Express each fraction or mixed number as a percent

Mathematics
1 answer:
vladimir1956 [14]2 years ago
3 0
So,

#1: \frac{5}{8}

We know that \frac{1}{8} = 0.125, or 12.5%.
Therefore, we just have to multiply 12.5% by 5 to get \frac{5}{8}  in percent form.

12.5(5) = 62.5

\frac{5}{8}  as a percent is 62.5%.


#2: 2  \frac{4}{7}

2 \frac{4}{7} = 200% + \frac{4}{7}

4/7 rounded to the nearest thousandth is 0.5714, or 57.14%.

200% + 57.14% = 257.14%
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If
Nitella [24]

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

<h3>How to find the production level that'll maximize profit?</h3>

The cost function, C(x) is given by 12000 + 400x − 2.6x² + 0.004x³ while the demand function, P(x) is given by 1600 − 8x.

Next, we would differentiate the cost function, C(x) to derive the marginal cost:

C(x) = 12000 + 400x − 2.6x² + 0.004x³

C'(x) = 400 − 5.2x + 0.012x².

Also, revenue, R(x) = x × P(x)

Revenue, R(x) = x(1600 − 8x)

Revenue, R(x) = 1600x − 8x²

Next, we would differentiate the revenue function to derive the marginal revenue:

R'(x) = 1600 - 8x

At maximum profit, the marginal revenue is equal to the marginal cost:

1600 - 8x = 400 − 5.2x + 0.012x

1600 - 8x - 400 + 5.2x - 0.012x² = 0

1200 - 2.8x - 0.012x² = 0

0.012x² + 2.8x - 1200 = 0

Solving by using the quadratic equation, we have:

x = 220.40 or x = -453.73.

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

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Step-by-step explanation:

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a recipe calls for a total of 3 2/3 cups of flour and sugar. it the recipe calls for 1/4 cup of sugar, how much flour is needed?
zavuch27 [327]

Answer:

This is very detailed as I wish to make some principles about fractions clear.

3

5

12

Explanation:

This question boils down to  

3

2

3

−

1

4

A fractions structure is that of:

count

size indicator of what you are counting

→

numerator

denominator

You can not directly add or subtract the counts (numerators) unless the size indicators (denominators) are the same.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Consider  

3

2

3

Write as  

3

+

2

3

Multiply by 1 and you do not change the value. However, 1 comes in many forms so you can change the way something looks without changing its true value

[

3

×

1

]

+

2

3

[

3

×

3

3

]

+

2

3

 

9

3

   

+

2

3

 

=

 

11

3

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Putting it all together

3

2

3

−

1

4

 

→

 

11

3

−

1

4

But the size indicators are not the same. I chose to make them become 12

11

3

−

1

4

 

→

 

[

11

3

×

1

]

−

[

1

4

×

1

]

               

→

 

[

11

3

×

4

4

]

−

[

1

4

×

3

3

]

               

→

     

44

12

     

−

 

3

12

Now we may subtract the counts

               

→

 

44

−

3

12

 

=

 

41

12

But this is the same as  

12

12

+

12

12

+

12

12

+

5

12

                         

=

 

1

2

+

2

1

2

+

2

1

2

+

5

12

 

=

 

3

5

12


Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
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