Question

What is the area of this parallelogram?

Answer 1

A = bh = 11 x 8 = 88
answer
88 m²

Answer 2

Hello!
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To find the area of this parallelogram, we need to divide it into 3 parts -- the left triangle, the rectangle, and the right triangle.

STEP 1) Finding area of triangle ADE.

Formula:
$a = \frac{1}{2} (b \times h)$
Plug in the base, 4 meters, and the height, 8 meters.
$a = \frac{1}{2} (4 \times 8)$
Multiply the product by half.
$a = \frac{1}{2} (32)$
$a = 16$
So the area of Triangle ADE is 16 square meters.

STEP 2) Finding area of ractangle DFBE.

Formula:
$a = b \times h$
To find area of a rectangle, multiply its base (length) by its height (width).

Plug in the base, 7 meters, and the height, 8 meters.

$a = 7 \times 8$
$a = 56$
So the area of Rectangle DFBE is 56 square meters.

STEP 3) Finding area of triangle FBC.

The two triangles are equilateral triangles, they have the same measurement.

$a = 16$
So the area of Triangle FBC is 16 square meters.

STEP 4) Finding the area of the composite figure.

To find the area of the figure, add up all the area(s) of the smaller shapes.

$a = 16 + 56 + 16$
Combine like terms.
$a = 32 + 56$
$a = 88$
So the area of the Composite Figure is 88 square meters.

CORRECT ANSWER) B. 88 square meters