The value of csc C in fraction and in decimal form is as follows:
csc C = 5 / 3
csc C = 1.66666666667
Using trigonometric ratio,
secant A = 1 / cos A = hypotenuse / adjacent
Therefore,
sec A = 5/3
sec A = 1 / cos A
cos A = adjacent / hypotenuse
cos A = 3 / 5
A = cos⁻¹ 0.6
A = 53.1301023542
Therefore,
∠A = 53°
∠B = 90°
∠C = 180 - 143 = 37°
cosec C = 1 / sin C = hypotenuse / opposite
cosec C = 5 / 3
learn more about trigonometry here: brainly.com/question/25942962?referrer=searchResults
Answer:
the answer is multiple ............
<h3>
Answer:</h3>
(x, y) = (7, -5)
<h3>
Step-by-step explanation:</h3>
It generally works well to follow directions.
The matrix of coefficients is ...
![\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%264%5C%5C-5%263%5Cend%7Barray%7D%5Cright%5D)
Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...
![\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B26%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-4%5C%5C5%262%5Cend%7Barray%7D%5Cright%5D)
So the solution is the product of this and the vector of constants [-6, -50]. That product is ...
... x = (3·(-6) +(-4)(-50))/26 = 7
... y = (5·(-6) +2·(-50))/26 = -5
The solution using inverse matrices is ...
... (x, y) = (7, -5)
If is an acute triangle, all the angles should be acute angles.
180-38=142°
142-69=73°
So your answer is 69°, lovely~
Answer:
bottom left
Step-by-step explanation:
