Answer:
10.5618feet, 0.8125sec
Step-by-step explanation:
Given the height reached by the catapult expressed by the equation H=-16T^2+26T
At the maximum height, the velocity of the object is zero, hence;
v = dh/dt = 0
-32t + 26 = 0
-32t = -26
t = 26/32
t = 0.8125secs
Hence it will attain the maximum height after 0.8125second
Substitute t = 0.8125s into the expression to get the maximum height
H=-16t^2+26t
H = -16(0.8125)^2 + 26(0.8125)
H = -16(0.6602) + 21.125
H = -10.5632+21.125
H = 10.5618
hence the maximum height reached by the ball is 10.5618feet
Answer:
which function describes this table of values x y 0 0
Assuming there is no line under the "less than" sign, this means D + 4 < 7 solves to D < 3, which is what I'm assuming you got. This is found by subtracting 4 from both sides.
Writing D < 3 means D is some number less than 3. A solution is just that. You cannot pick 3 itself because 3 is not less than 3. But you can pick something like 2 since it is less than 3.
D+4 < 7
2+4 < 7 ... replace D with 2
6 < 7 ... true
Or D could be 1
D+4 < 7
1+4 < 7
5 < 7 .... true
and so on.
I believe the answer is "A"
Answer: That would be 549.5 cubic inches of cat litter (approximately).
Step-by-step explanation: The cylindrical storage container has a height of seven inches and a radius of five inches. To know how much cat litter would fill it requires us to calculate the volume of the container.
The volume of a cylinder is given as,
Volume = Pi x r^2 x h
Where r is the radius, h is the height and Pi shall be taken as 3.14
We can now substitute for the known values as follows;
Volume = 3.14 x 5^2 x 7
Volume = 3.14 x 25 x 7
Volume = 549.5
Rounded to the nearest tenth, the container would be filled with 549.5 cubic inches of cat litter.
