The extra X chromosome is received from mother.
<h3><u>Explanation</u>:</h3>
Klinefelter's syndrome is the condition of chromosomal aberration where the person has an extra X chromosome. This means the genotype of the person is 44+XXY and the total chromosome number is 47. This condition is achieved due to inappropriate meiotic division and one of the sperm or ovum has the an extra X chromosome.
Here both the parents are normal in terms of colour vision. So the father cannot have the gene of colour blindness because if it was present, then father would have been colour blind because he has only one X chromosome per cell. So its present in mother who is heterozygous in terms of colour blind gene. So the extra X chromosome also came from her which made the presence of two defective X chromosomes in the offspring and made it colour blind.
The farmer's action most likely have a negative impact on the ecosystem because may be there is no predator or controlling agent of that bird.
<h3>Why introduction of new bird cause problem?</h3>
We know that one organism is responsible for controlling the population of other organism so if such type of controlling agent is present, the organism grow rapidly and can harm the whole ecosystem.
So we can conclude that farmer's action have a negative impact on the ecosystem due to presence of no predator or controlling agent of that bird.
Learn more about bioagent here: brainly.com/question/842527
The correct answer is that the yolk provides nutrients for the embryo. Hope this helps.
I have provided the options below:
a. 150
b. 225
c. 300
d. 450
e. 75
Answer:
150
Explanation:
Hardy-Weinberg law states, the allelic frequencies of a gene that is, q and p follow the relationship p^2+q^2+2pq = 1, if the population is in equilibrium.
Therefore p^2+q^2+2pq = 1, can be used to calculate the percentage of the allelic frequencies i.e. p^2 and q^2
Allelic frequency = 0.75.
Therefore, the percentage of the allele in the population would be given by
0.75^2 = 0.5625 = 56%.
And the total number of individuals with this allele in the population:
number of individuals = 56×300÷100
= 168 or
150 nearest figure.
