Answer:
min = a_1
for i:= 2 to n:
if 
< min then min =
return min
Step-by-step explanation:
We call the algorithm "minimum" and a list of natural numbers 
So lets first set the minimum to 
min = a_1
now we want to check all the other numbers.
We can use a simple for loop, to find the minimum
min = a_1
for i:= 2 to n:
if < min then min =
return min
Answer:
42 m
Step-by-step explanation:
l+1 * (b+1) = lb+22
lb+b+l+1 = lb+22
l+b=21
perimeter = 42 m
<span> 2 square root of 7 − square root of 28
= 2</span>√7 - √28
= 2√7 - 2√7
= 0
Answer:
Move all terms to the left side of the equation and simplify.
3x²−12x−21=0
Use the quadratic formula to find the solutions.
(−b±√b²−4(ac))/2a
Substitute the values a=3, b=−12, and c=−21 into the quadratic formula and solve for x.
(12±√(−12)²−4⋅(3⋅−21)0/2⋅3 Simplify => x=2±√11
The result can be shown in multiple forms.
Exact Form: x=2±√11
Decimal Form: x=5.31662479…,−1.31662479…
Step-by-step explanation:
