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3 years ago

5

Can someone plz help me out

1 answer:

Shkiper50 [21]3 years ago

7 0

2.false. This is so as 3 to 4 or 3/4=0.75 while 4 to 3 is 1.333333333333333 infinite.

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How do you find three consecutive even integers with a sum of -84. Please help!

mote1985 [20]

3 consecutive even integers : x, x + 2, x + 4

x + (x + 2) + (x + 4) = -84.....combine like terms
3x + 6 = - 84.......subtract 6 from each side
3x = -84 - 6
3x = - 90...divide both sides by 3
x = -90/3
x = -30

x + 2 = -30 + 2 = -28
x + 4 = -30 + 4 = -26

so ur 3 numbers are : -26, -28, -30

6 0

3 years ago

Read 2 more answers

In apirl is rained 1/4 of a inch on 15 diffret day how many inches of rain fell

Ne4ueva [31]

In $15$ diffret days $15/4$ inches of rain fell in April month if every day rained $1/4$ of a inch .

How to find the rain fell in $15$ diffret days ?

We know that rain in every day is $1/4$ of a inch

So for $15$ days

$1/4+1/4+1/4+......15times\\=15/4$

So in $15$ diffret days in April rain fell is $15/4$ inches.

Learn more about the rain fall is here :

brainly.com/question/28049911

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8 0

1 year ago

The market and Stock J have the following probability distributions:

denis-greek [22]

Answer:

1) $E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

2) $E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

3) $E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

4) $E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

Step-by-step explanation:

For this case we have the following distributions given:

Probability M J

0.3 14% 22%

0.4 10% 4%

0.3 19% 12%

Part 1

The expected value is given by this formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

Part 2

$E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

Part 3

We can calculate the second moment first with the following formula:

$E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

Part 4

We can calculate the second moment first with the following formula:

$E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

8 0

3 years ago

Find arc DC pls I’m stuck on this problem

stepan [7]

Answer:

$m\overset{\Large\frown}{ABC} \: = \: 196°$

8 0

2 years ago

What is the value of the expression below when y=10? 5y+3

trasher [3.6K]

I think it is 53 that’s what i would put if i were u

7 0

2 years ago