Answer:
Water needed for pool = 486 cubic feet
Plastic liner required for the pool = 298.3 feet
Step-by-step explanation:
Top view of the pool is a composite figure, having one rectangle and a trapezoid.
1). Water needed for the pool = volume of the pool
Volume of the pool = Area of the base × Depth
= (Area of the rectangle + Area of the trapezoid)× depth
Area of the trapezoid = 
= 
= 105 ft²
Area of the rectangle = Length × width
= 11 × 1.5
= 16.5 ft²
Now, volume of the pool = (105 + 16.5) × 4
= 121.5 × 4
= 486 cubic feet
b). Liner required = surface area of the pool excluding top
= Surface area of the walls + Area of the pool base
= (Perimeter of the pool) × depth + area of the base
= (12 + 11 + 1.5 + 10.7 + 9)×4 + 121.5
= 176.8 + 121.5
= 298.3 square feet
Therefore, amount of water required = 486 cubic feet
liner needed = 298.3 square feet
Do you mean cube root because the cube root of 24 is 2.88 and other repeating decimals
Answer:
3x+2y
Step-by-step explanation:
Find the rectangles attached
Area of a rectangle = Length * Width
A = A1+A2
given
A = 30cm²
A1 = 3 * x
A1 = 3x
A2 = 2*y
A2 = 2y
Substitute
30 = 3x+2y
Hence the required equation is 3x+2y = 30
Answer:
Step-by-step explanation:
The diagram shows lines passing through the points of two equations.
We will determine the points through which the lines pass through on the graphs.
Looking at the line on the right hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 4
x2 = 3, x1=0
Slope, m = (0-4)/3-0
Slope = -4/3
Recall the equation of a straight line is y = mx + c
Where c is the intercept.
So the equation is y
y = -4x/3 + 4
Looking at the line on the left hand side of the graph, the slope is
(y2-y1)/x(2-x1) where
y2= 0, y1 = 2
x2 = -1, x1 =0
Slope, m = (0-2)/-1-0
Slope = -2/-1 = 2
Applying equation of a straight line is y = mx + c
The equation
y = 2x + 2
So the equations are
-4x/3 + 4. If x lesser than or equal 0
2x + 2. If x greater than 0
Answer:
https://forms.gle/VqfekaGgk8cfJhPW9
Step-by-step explanation: