Answer:
54%
Explanation:
So, we have that the "magnitude of its displacement from equilibrium is greater than (0.66)A—''. Thus, the first step to take in answering this question is to write out the equation showing the displacement in simple harmonic motion which is = A cos w×t.
Therefore, we will have two instances t the displacement that is to say at a point 2π/w - a2 and the second point at a = a2.
Let us say that 2π/w = A, then, we have that a = A cos ^-1 (0.66)/2π. Also, we have that a2 = A/2 - A cos^- (0.66) / 2π.
The next thing to do is to calculate or determine the total length of of the required time. Thus, the total length is given as:
2a1 + ( A - 2a2) = 2A{ cos^-1 (0.66)}/ π.
Therefore, the total percentage of the period does the mass lie in these regions = 100 × {2a1 + ( A - 2a2) }/A = 2 { cos^-1 (0.66)}/ π × 100 = 54%.
Thus, the total percentage of the period does the mass lie in these regions = 54%.
They flow i guess but dont quote me on that
Answer:
Explanation:
The remaining amount of a radioactive isotope is found as the product of the original amount by (1/2) raised to the number of half-lives elapsed. The formla is:
Where M is the remaining amoun, M₀ i s the initial amount, and n is the number of half-lives.
Here, 1/64 of the original carbon-14 remained, meaning that M/M₀ = 1/64.
Then, you can substitute in the equation and solve:
Then, 6 half-lives elapsed since the mastodon died and the remains were dated.
Then, you must multiply 6 by the <em>half-life </em>time:
- 6 × 5730 years = 34,380 years ← answer
Given:
u = 0, initial velocity
v = 125 m/s, final velocity
s = 0.0800 m, distance traveled
9.20 g, the mass of the pellet
If the acceleration is a, then
0² + 2*(a m/s²)*(0.800 m) = (125 m/s)²
1.6a = 15625
a = 9765.625 m/s²
Calculate the force.
F = (9.20 x 10⁻³ kg)*(9765.625 m/s²) = 98.84 N
Answer: 98.8 N (nearest tenth)
<h2><em>what is the correct order of the steps in the scientific </em><em>method</em></h2>
- <em>Make a hypothesis, test the hypothesis, analyze the results, ask a question, draw conclusions, communicate results.</em>
<em>hope</em><em> </em><em>it</em><em> helps</em>
