It is 6 yrs
.
away from the sun
If we assume that Earth is a solid sphere, then I = (2/5)mr² = (2/5) * 5.98e24kg * (6.371e6m)² = 9.71e37 kg·m²
torque τ = Iα, but also τ = F*r = 3.98e7N * 6.371e6m = 2.54e14 N·m Since τ = τ, 2.54e14 N·m = 9.17e37kg·m² * α α = 3.61e-23 rad/s²
ωo = 2πrads / (24h*3600s/h) = 7.27e-5 rad/s ω1 = 2πrads / (28h*3600s/h) = 6.23e-5 rad/s
Plug in numbers t = 2/5 * (5.98 * 10^24 kg) * (6.37*10^6 m) * (7.27 * 10^-5 rad/s - 6.23 * 10^-5 rad/s) / (3.98*10^7 N) = 3.98*10^22 s = 1.26*10^17 yrs
Answer:
given,
initial velocity = 11.5 m/s
acceleration = 0.5 m/s²
time = 7 s
a) using equation of motion
v = u + a t
v = 11.5 + 0.5 × 7
v = 15 m/s
b)
s = 92.75 m
distance traveled by racer with final velocity
d = 300 - 92.75
= 207.25 m
time spend to travel 207.25
t = 13.82 s
total time spent to travel 300m
t = 7 + 13.82
t = 20.82 s
time required to travel 300 m with initial velocity
= 26.09 s
time saved due to acceleration
t = 26.09 - 20.82 = 5.27 s
c) second racer is 5 m apart from the first one
distance traveled by the second racer till first one finishes the race
distance behind the leader
d = 300 -5 -245.676 = 49.34 m
time behind the winner
Answer:
It takes a little, be patient.
Answer:
North America, Europe, and most of Asia.
<u><em>I hope this helped at all.</em></u>