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vivado [14]
3 years ago
14

Two adjoining plane mirrors are separated by an angle of 100°. Light is incident on the first mirror at an angle of 70°. The lig

ht reflects toward the second mirror and is then reflected from it. At what angle is the light reflected from the second mirror?

Physics
2 answers:
Ludmilka [50]3 years ago
8 0

Answer:

The angle is the light reflected from the second mirror is 30°

Explanation:

Given that,

Angle between mirrors = 100°

Angle of incident = 70°

We know that,

The incident angle is equal to the reflected angle.

We need to calculate the angle BCA

According to figure,

In \Delta ABC,

\angle ABC+\angle BCA+\angle C=180

Put the value into the formula

20+100+\angle BCA=180

\angle BCA = 60

We need to calculate the angle is the light reflected from the second mirror

Using relation of incident and reflection

i+\angle BCA=90

i=90-60=30^{\circ}

We know that, i = r

So, i=r=30°

Hence, The angle is the light reflected from the second mirror is 30°

vladimir1956 [14]3 years ago
4 0

Answer:

The angle is the light reflected from the second mirror is 30°

Explanation:

Given that,

Angle between mirrors = 100°

Angle of incident = 70°

We know that,

The incident angle is equal to the reflected angle.

We need to calculate the angle BCA

According to figure,

In ,

Put the value into the formula

We need to calculate the angle is the light reflected from the second mirror

Using relation of incident and reflection

We know that, i = r

So, i=r=30°

Hence, The angle is the light reflected from the second mirror is 30°

Read more on Brainly.com - brainly.com/question/13152660#readmore

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Hi there!

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1 year ago
A uniform solid disk rolls without slipping down an incline making an angle θ with the horizontal. What is its acceleration? (En
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Answer:

aCM = (2/3)*g*Sin θ

Explanation:

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In order to get the linear acceleration of the object’s center of mass, aCM ,

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Since the object rolls without  slipping there is a force of  friction (Ff) acting on the object,  at it’s point of contact with the  incline, in the direction up  the incline.

Newton’s 2nd Law gives then for acceleration down the incline

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The force of friction also causes a torque around the center of mass

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This is used in the expression  derived from the 2nd Law:

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The objects angular acceleration is related to the linear acceleration  of the edge that contacts the incline by

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Since the object rolls without  slipping this has the same  magnitude as aCM so we have  that

α = aCM / R

Using this in

m*g*Sin θ - (I*α / R) = m*g*Sin θ - (I*(aCM / R) / R) = m*aCM

⇒  aCM = (m*g*Sin θ*R²) / (I + m*R²)

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we get

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Answer

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