Answer:
99
Step-by-step explanation:
plzmark brainliest
Answer:
answer choice c is correct
:)
hope that helped. <3
<em>bye now! </em>
<em>have a nice day too <3.</em><u><em> k bye</em></u>
Answer:
Step-by-step explanation:
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Description Equation
Derivative of a Constant Derivative of a Constant
Derivative of a Variable to the First Power Derivative of a Variable to the First Power
Derivative of a Variable to the nth Power Derivative of a Variable to the nth Power
Derivative of an Exponential Derivative of an Exponential
Derivative of an Arbitrary Base Exponential Derivative of an Arbitrary Base Exponential
Derivative of a Natural Logarithm Derivative of a Natural Logarithm
Derivative of Sine Derivative of Sine
Derivative of Cosine Derivative of Cosine
Derivative of Tangent Derivative of Tangent
Derivative of Cotangent Derivative of Cotangent
Answer:
The stone will be in flight for 3 seconds
Step-by-step explanation:
Given the equation;
d = -16t^2 + vt + h
Where;
v = the initial velocity
h = the initial height
Given;
v = 48 ft/s
h = 0
Substituting into function d;
d = -16t^2 + 48t + 0
d = -16t^2 + 48t
At the point of launch and the point of landing d = 0.
We need to calculate the values of t for d to be equal to zero.
d = -16t^2 + 48t = 0
-16t^2 + 48t = 0
Factorising, we have;
16(-t+3)t = 0
So,
t = 0 or -t+3 = 0
t= 0 or t =3
Change in t is;
∆t = t2 - t1 = 3 - 0
∆t = 3 seconds.
The stone will be in flight for 3 seconds.
