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3 years ago

14

If you flip a coin and roll a

2 answers:

Greeley [361]3 years ago

4 0

Answer:

1/12

Step-by-step explanation:

kkurt [141]3 years ago

4 0

Answer:

1/12

Step-by-step explanation:

Because there are 6 sides on the die and only one 2 the probability of rolling a 2 is 1/6

There are two sides of a coin and 1 of them is heads which makes the probability of fliping a coin and landing on heads 1/2

1/2 x 1/6 = 1/12

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In Exercises 51−56, the letters a, b, and c represent nonzero constants. Solve the equation for x

Nonamiya [84]

Answer:

x = -8/b

Step-by-step explanation:

2bx – bx = -8

Combine like terms

bx = -8

Divide by b

bx/b = -8/b

x = -8/b

5 0

3 years ago

Ella is a landscape photographer. One weekend at her gallery she sells a total of 52 prints for a total of $2,975. A small paint

rosijanka [135]

<h2>Answer:37 paintings of $50 and 15 paintings of $75</h2>

Step-by-step explanation:

Let $x$ be the number of paintings Ella sells for $ $50$ .

Let $y$ be the number of paintings Ella sells for $ $75$ .

Profit made through $ $50$ paintings is $50x$

Profit made through $ $75$ paintings is $75y$

So,total profit is given by $50x+75y$

It is given that total profit is $ $2975$

So, $50x+75y=2975$ ..(i)

Given that the total number of prints is $52$

So, $x+y=52$ ..(ii)

using (i) and (ii),

$50x+75(52-x)=2975\\50x+3900-75x=2975\\25x=925\\x=37$

$y=52-x=52-37=15$

7 0

3 years ago

Read 2 more answers

James is reading a book that is 1400 pages he will read the same number of pages each day if he reads the book in 7 days how man

Novay_Z [31]

He will read 200 pages a day.

7 0

3 years ago

Read 2 more answers

A chord is 48 cm long and is 7 cm from the center of the circle. What is the length of the radius (r) of the circle?

ra1l [238]

Answer:

95

Step-by-step explanation:

4 0

3 years ago

(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago