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3 years ago

What is the square root of 244?

Mathematics

1 answer:

adell [148]3 years ago

8 0

The square root of 224 is: 14.9666295471

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- En una tienda, durante las rebajas, encontramos los siguientes carteles: “ De 150 euros a 90 euros” y “De 40 euros a 24 euros”

Nana76 [90]

Answer:dwadwdwd

Step-by-step sadawdwdwadwdwexplanation:

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2 years ago

FIRST ANSWER GETS BRAINLIEST (ANSWER HAS TO BE IN DETAIL)

agasfer [191]

Answer:

2975.978

Step-by-step explanation:

This is pretty easy, just keep the order going on.

Here is the CORRECT order:

2 Thousand(s)

9 Hundred(s)

7 Ten(s)

5 One(s)

decimal part because there is th after each type of number (ex. thousandth)

9 Tenth(s)

7 Hundredth(s)

8 Thousandth(s)

3 0

1 year ago

Read 2 more answers

F(x) = (128/127)(1/2)x, x = 1,2,3,...7. determine the requested values: round your answers to three decimal places (e.g. 98.765)

Marrrta [24]

A.
$\mathbb P(X\le 1)=\mathbb P(X=1)=\dfrac{128}{127}\left(\dfrac12\right)^1=\dfrac{64}{127}$

b.
$\mathbb P(X>1)=1-\mathbb P(X\le1)=1-\dfrac{64}{127}=\dfrac{63}{127}$

c.
$\mathbb E(X)=\displaystyle\sum_{x=1}^7 x\,f_X(x)=\frac{64}{127}\sum_{x=1}^7 x\left(\frac12\right)^{x-1}$

Suppose $f(y)=\displaystyle\sum_{x=0}^7 y^x$ . Then $f'(y)=\displaystyle\sum_{x=1}^7 xy^{x-1}$ . So if we can find a closed form for $f(y)$ , in terms of $y$ , we can find $\mathbb E(X)$ by evaluating the derivative of $f(y)$ at $y=\dfrac12$ .

$f(y)=\displaystyle\sum_{x=0}^7 y^x=y^0+y^1+y^2+\cdots+y^6+y^7$
$y\,f(y)=y^1+y^2+y^3+\cdots+y^7+y^8$
$f(y)-y\,f(y)=y^0-y^8$
$(1-y)f(y)=1-y^8$
$f(y)=\dfrac{1-y^8}{1-y}$
$\implies f'(y)=\dfrac{7y^8-8y^7+1}{(1-y)^2}$
$\implies\mathbb E(X)=\dfrac{64}{127}f'\left(\dfrac12\right)=\dfrac{64}{127}\times\dfrac{247}{64}=\dfrac{247}{127}$

d.
$\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$

We find $\mathbb E(X^2)$ in a similar manner as in (c).

$\mathbb E(X^2)=\displaystyle\sum_{x=1}^7 x^2\,f_X(x)=\frac{32}{127}\sum_{x=1}^7x^2\left(\frac12\right)^{x-2}$

Now,

$f(y)=\displaystyle\sum_{x=0}^7y^x$
$\implies f'(y)=\displaystyle\sum_{x=1}^7xy^{x-1}$
$\implies f''(y)=\displaystyle\sum_{x=2}^7x(x-1)y^{x-2}$

We know that

$f''(y)=-\dfrac{42y^8-96y^7+56y^6-2}{(1-y)^3}$
$\implies f''\left(\dfrac12\right)=\dfrac{219}{16}$

We also have

$f''(y)=\displaystyle\sum_{x=2}^7x(x-1)y^{x-2}$
$f''(y)=\displaystyle\sum_{x=2}^7x^2y^{x-2}-\sum_{x=2}^7xy^{x-2}$
$f''(y)=\displaystyle\frac1{y^2}\left(\sum_{x=2}^7x^2y^x-\sum_{x=2}^7xy^x\right)$
$f''(y)=\displaystyle\frac1{y^2}\left(\bigg(\sum_{x=1}^7x^2y^x-y\bigg)-\bigg(\sum_{x=1}^7xy^x-y\bigg)\right)$
$f''(y)=\displaystyle\frac1{y^2}\left(\sum_{x=1}^7x^2y^x-\sum_{x=1}^7xy^x\right)$

so that when $y=\dfrac12$ , we get

$\dfrac{219}{16}=4\left(\dfrac{127}{128}\mathbb E(X^2)-\dfrac{127}{128}\mathbb E(X)\right)\implies\mathbb E(X^2)=\dfrac{685}{127}$

Then

$\mathbb V(X)=\dfrac{685}{127}-\left(\dfrac{247}{127}\right)^2=\dfrac{25,986}{16,129}$

6 0

3 years ago

50 points for this question! Geometry question! Please show all steps

alexira [117]

Answer:

Step-by-step explanation:

First we will find the length of y

Two secants intersect outside the circle.

The outside piece times the total length on one side equals the outside length times the total length on the other side

14* 30 = y* (32+y)

420 =32y + y^2

Subtract 420

0 =y^2 +32y -420

Solving for y

Factor

0 = (y+42)(y-10)

y = -42 y= 10

Y can't be negative so y=10

Now we find x

A secant and a tangent intersect outside the circle.

BA ^2 = Outside length * Total length

15^2 = x* (x+16)

225 = x^2 +16x

Subtract 225

0 = x^2 +16x-225

Solving for x

0=(x-9) (x+25)

x=9 x=-25

Since we can't be negative x=9

Now we can use the Pythagorean theorem to see if the triangle is right acute or obtuse

(15)^2 + (9+16+14) ^2 vs42^2 (32+10)^2

225 + 39^2 vs 42^2

225+1521 1764

1746 <1764

Obtuse triangle

8 0

3 years ago

Read 2 more answers

How can we classify the following shape?

DerKrebs [107]

Answer:

Parallelogram

Step-by-step explanation:

Parallelograms have 2 sets of parallel sides, hence the name.

3 0

2 years ago