How to write algebraic equations from word problems?

Mathematics

1 answer:

Whitepunk [10]4 years ago

5 0

It's January, they have till July => 6 months including January

half of $8000 is $4000 in 6 months
4000/6 = $666.66 per month
Johnny should save that much money each month

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A skyscraper is 1,150 feet above ground level. It extends 35 feet below ground level. What is the total length of the skyscraper

Ne4ueva [31]

1,150ft + 35ft = 1,185ft

The reason you wouldnt subtract would be that you cant have negative 35 ft. You add the two heights together to produce your answer.

6 0

4 years ago

The height of a trapezoid is 8 inches and its area is 96 in one base of the trapezoid is 6 inches longer than the other base wha

yan [13]

First is to get the given data that we might be able to use for computation.
H = 8 inches
Area = 96
B1 = B1
B2 = B1+6

Next is to know the area of a trapezoid
Area = H x (B1 + B2)/2
96 = 8 x (B1 + B1 + 6) / 2
96 = 8 x (2B1 + 6) /2
96 = 4 x (2B1 + 6)
14 = 2B1 + 6
2B1 = 8
B1 = 4
B2 = 10

3 0

4 years ago

Read 2 more answers

How many sides does a parallelogram have?<br> OA) 2<br> OB) 4<br><br> OD 6

KonstantinChe [14]

Answer:

OB: 4 sides

Step-by-step explanation:

A parallelogram has 4 sides. It is a flat shape with opposite sides parallel and equal in length. Opposite angles are equal.

In the picture below, angles "a" are the same, and angles "b" are the same.

In the case of a parallelogram where all angles are right angles, is a rectangle.

4 0

3 years ago

Some parts of California are particularly earthquake- prone. Suppose that in one metropolitan area, 25% of all homeowners are in

aleksandrvk [35]

Answer:

a. Binomial random variable (n=4, p=0.25)

b. Attached.

c. X=1

Step-by-step explanation:

This can be modeled as a binomial random variable, with parameters n=4 (size of the sample) and p=0.25 (proportion of homeowners that are insured against earthquake damage).

a. The probability that X=k homeowners, from the sample of 4, have eartquake insurance is:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{4}{k} 0.25^{0}\cdot0.75^{4}$

The sample space for X is {0,1,2,3,4}

The associated probabilties are:

$P(x=0) = \dbinom{4}{0} p^{0}(1-p)^{4}=1*1*0.3164=0.3164\\\\\\P(x=1) = \dbinom{4}{1} p^{1}(1-p)^{3}=4*0.25*0.4219=0.4219\\\\\\P(x=2) = \dbinom{4}{2} p^{2}(1-p)^{2}=6*0.0625*0.5625=0.2109\\\\\\P(x=3) = \dbinom{4}{3} p^{3}(1-p)^{1}=4*0.0156*0.75=0.0469\\\\\\P(x=4) = \dbinom{4}{4} p^{4}(1-p)^{0}=1*0.0039*1=0.0039\\\\\\$