Answer:
I don't know if I understood the question correctly, but this is what I have...
Step-by-step explanation:
If the "x" is a variable:
(2x-3)-(1-1)=
2x-3
If th "x" is a multiplication sign:
(2x-3)-(1-1)=
-6-0=
-6
i hope this helps
Answer:
f(x)=(x−3)2−5
Find the properties of the given parabola.
Direction:
Vertex: (3,−5)
Focus: (3,−194)
Axis of Symmetry: x=3
Directrix: y=−214
Select a few x
values, and plug them into the equation to find the corresponding y values. The x
values should be selected around the vertex.
x y
1 -1
2 -4
3 -5
4 -4
5 -1
Graph the parabola using its properties and the selected points.
Direction:
Vertex: (3,−5)
Focus: (3,−194)
Axis of Symmetry: x=3
Directrix: y=−214
x y
1 -1
2 -4
3 -5
4 -4
5 -1
2 inches in between each, start off on the edge go in 3 inches secound brace, than finsh on the final edge
Answer:
Find the linearization L(x,y) of the function at each point. f(x,y) = x2 + y2 + 1 a. (4,0) b. (2,0) a. L(x,y) = Find the linearization L(x,y,z) of the function f(x,y,z) = 1x2 + y2 +z2 at the points (7,0,0), (3,4,0), and (4,4,7). The linearization of f(x,y,z) at (7,0,0) is L(x,y,z)= (Type an exact answer, using radicals as needed.)
Here’s the answer for your question. The A/= it means the answer is okay.