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3 years ago

1/3(x+4)=20 need help

2 answers:

34kurt3 years ago

7 0

$\frac{1}{3} (x+4) = 20 \\ \\ simplify \\ \\ \frac{1}{3} x + \frac{4}{3} = 20 \\ \\ Subtract >>by >> \frac{4}{3} \\ \\ \frac{1}{3} x + \frac{4}{3} - \frac{4}{3} = 20 - \frac{4}{3 \\ \\} \\ \\ Divide > by > \frac{1}{3} \\ \\ and > your>answer>is = x = 56$

sukhopar [10]3 years ago

5 0

1/3(x+4)=20

1/3x+4/3=20

1/3x=56/3

x= (56/3) / (1/3)

x= 56

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4 years ago

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AURORKA [14]

G(x) = 3x² - 5x + 7
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This equation cannot be solved because of a few reasons,

1. This equation didn't show that it equals to 0.
2. Even if it equals to zero, square root of a negative number cannot be solved.
(I will show you what I mean)

-3x² + 5x - 7
is the same as
3x² - 5x + 7
by shifting the equation,

for example,
1 - 3 = -2
shifting other side
2 = -1 + 3

using 3x² - 5x + 7 to solve,

$Solve\ using\ the\ formular\ \ \boxed{ x= { \frac{-b \pm \sqrt{b^2-4ac} }{2a} } }$
a = 3
b = -5
c = 7
$x= { \frac {-(-5) \pm \sqrt{ (-5)^2-4(3)(7) } }{2(3)} }$
$x= { \frac {5 \pm \sqrt{-59} }{6} }$

∴This equation cannot be solved.

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3 years ago