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BaLLatris [955]
3 years ago
8

This cube and cuboid have the same volume. The length, width and height of the cuboid are all different whole numbers. Suggest w

hat they might be. 4 cm 4 cm width 4 cm height length ​
Mathematics
1 answer:
Zanzabum3 years ago
4 0

Answer:

4hdunzkzmfindudjdkzmd

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andrew11 [14]
They would have to pay the hourly cost if they played around 7 games because 7 games would equal to the cost of one hour.
6 0
3 years ago
What does find the constant rate of change mean?
natulia [17]

The change of the cost changes when the pounds of ham changes. When the pounds of ham is 0, it costs 0 dollars. When the pounds of ham is 3, it costs 12 dollars. The cost changes consistently with the pounds of ham. They change together. Every time the pounds of ham goes up by 3, the cost goes up by 12.

7 0
3 years ago
Please someone help me I don’t understand
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Remark

The solution to this is to add the two vertically opposite arcs and take 1/2 of the result to get the intersecting angle of the chords.

Solution

<x = 1/2 (arc measure of 116 + 74)

<x = 1/2 (190)

<x = 95

8 0
2 years ago
Square root of: (q+3)*(q+6)
AnnyKZ [126]
To factor (q+3)(q+6)
           q^2+6q+3q+18
              q^2+9q+18
              (q+9)(q+2)
3 0
3 years ago
Ed signed up for a weight-loss program. The table shows his weight in pounds of the terms of the number of weeks since he began
scoray [572]
Ed : (0,205)(4,197)
slope(m) = (197 - 205) / (4 - 0) = -8/4 = -2

y = mx + b
slope(m) = -2
(0,205)...x = 0 and y = 205
time to sub
205 = -2(0) + b
205 = b
equation is : y = -2x + 205...so Ed loses 2 lbs per week

Eric :
y = -1.5x + 200...so Eric loses 1.5 lbs per week

when they started, Ed weighed 205 lbs and Eric weighed 200 lbs

* of the two, Eric loses fewer lbs per week. When the two began their respective weight-loss programs, Ed was heavier by 5 lbs.
4 0
3 years ago
Read 2 more answers
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