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attashe74 [19]
3 years ago
15

Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)

Mathematics
1 answer:
Elis [28]3 years ago
4 0

Answer:

Distance between point (3,4) and midpoint of line joining (8,10) and (4,6) = 5 units.

Step-by-step explanation:

Given:

Points:

A(3,4)\\B(8,10)\\C(4,6)

To find distance from point A to midpoint of  BC.

Midpoint M of BC:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\

M=(\frac{8+4}{2},\frac{10+6}{2})\\     [Plugging in points B(8,10)\ and\ C(4,6)]

M=(\frac{12}{2},\frac{16}{2})\\

M=(6,8)\\

Distance between A and M:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

D=\sqrt{(6-3)^2+(8-4)^2} \\   [Plugging in points A(3,4)\ and\ M(6,8)]

D=\sqrt{(3)^2+(4)^2} \\

D=\sqrt{9+16} \\

D=\sqrt{25} \\

D=\pm5

Since distance is always positive ∴ D= 5 units

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Step-by-step explanation:

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3 years ago
Word Problems : Subtract 18 rupees 9 paise from 75 rupees 80 paise<br><br>Write In Step by Step ​
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Answer:

Question

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Subtract the following:

A) 18 rupees 9 paise from 75 rupees 80 paise.

B) 49 rupees 79 paise from 123 rupees 68 paise.

Answer

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139.5k+ views

17.4k+ likes

Hint: Use decimal concept.

We know that, 1 rupee = 100 paise. We can reframe these questions as follows:

18 rupees 9 paise from 75 rupees 80 paise

18 rupees 9 paise can be represented as 18.09 rupees and 75 rupees 80 paise can be represented as 75.80 rupees. Now, on subtracting we’ll get,

75.80−18.09−−−−−− 57.71

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49 rupees 79 paise from 123 rupees 68 paise

49 rupees 79 paise can be represented as 49.79 rupees and 123 rupees 68 paise can be represented as 123.68 rupees. Now, on subtracting we’ll get,

123.68 −49.79−−−−−− 73.89

Which means 73 rupees 89 paise.

Note: We can also perform the subtraction by making all units the same that are paise and then subtract.

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3 years ago
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Evaluate f(x) = sqrt(5x + 4) for x = 12
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Answer is 8

Work Shown:

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f(12) = sqrt(60 + 4)

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Step-by-step explanation:

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Therefore, y = 9 since x = 0 on the y axis.

Picture of graph also attached :)


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