Answer:
B
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Hope this helped! Please tell me if I'm wrong!
Answer:
a. The probability that a customer purchase none of these items is 0.49
b. The probability that a customer purchase exactly 1 of these items would be of 0.28
Step-by-step explanation:
a. In order to calculate the probability that a customer purchase none of these items we would have to make the following:
let A represents suit
B represents shirt
C represents tie
P(A) = 0.22
P(B) = 0.30
P(C) = 0.28
P(A∩B) = 0.11
P(C∩B) = 0.10
P(A∩C) = 0.14
P(A∩B∩C) = 0.06
Therefore, the probability that a customer purchase none of these items we would have to calculate the following:
1 - P(A∪B∪C)
P(A∪B∪C) =P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C)
= 0.22+0.28+0.30-0.11-0.10-0.14+0.06
= 0.51
Hence, 1 - P(A∪B∪C) = 1-0.51 = 0.49
The probability that a customer purchase none of these items is 0.49
b.To calculate the probability that a customer purchase exactly 1 of these items we would have to make the following calculation:
= P(A∪B∪C) - ( P(A∩B) +P(C∩B) +P(A∩C) - 2 P(A ∩ B ∩ C))
=0.51 -0.23 = 0.28
The probability that a customer purchase exactly 1 of these items would be of 0.28
Answer:
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>
Step-by-step explanation:
1. Let's review the information provided to us to answer the question correctly:
μ of the time a group of boys run the mile in its secondary- school fitness test = 440 seconds
σ of the time a group of boys run the mile in its secondary- school fitness test = 40 seconds
2. Find the probability that a randomly selected boy in school can run the mile in less than 348 seconds.
Let's find out the z-score, this way:
z-score = (348 - 440)/40
z-score = -92/40 = -2.3
Now let's find out the probability of z-score = -2.3, using the table:
p (-2.3) = 0.0107
p (-2.3) = 0.0107 * 100
p (-2.3) = 1.1% (rounding to the next tenth)
<u>The probability that a randomly selected boy in school can run the mile in less than 348 seconds is 1.1%.</u>
Answer: The total money invested in the field will be $1,623.80
Step-by-step explanation:
step 1
Find the dimensions of the field
Let
x -----> the length of the field
y -----> the width of the field
p=2(x+y)
p(4.80)=1,584
p=330m
we know that
The perimeter of the field is equal to
so
330=2(x+y)----> equation A
x=4y-10 ------> equation B
substitute equation B in equation A and solve for y
330=2(4y-10+y)
165=(5y-10)
5y=165+10
y+35
Find the value of x
x=4(35)-10+130
therefore
The length of the field is 130 meters and the width of the field is 35 meters
step 2
Find the area of the field
The area of the field is
A=xy
substitute
A=(130)(35)=4,550m2
step 3
Find the number of bags of seed
Divide the area by 460
4,550/460=9.89 bags
Round up to the nearest whole number
9.89 bags=10 bags
step 4
Find the cost of the seed
(10 )(3.98)=$19.8
step 5
Find the total money invested in the field
1,584+$39.8=$1,623.80
