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zubka84 [21]
3 years ago
15

Am I correct can please someone tell me if I am correct I need help ASAP

Mathematics
1 answer:
nataly862011 [7]3 years ago
6 0

y = |x| is an absolute value function with vertex at (0, 0).

In a function, if you replace x with x - h, the graph shifts h units horizontally.

If you replace y with y - k, the graph shifts k units vertically.

Move the 7 to the left side.

y = |x - 4| - 7

y + 7 = |x - 4|

Now compare this function with the parent function y = |x|.

x has been replaced with x - 4. h = 4. The horizontal shift is 4 units to the right since 4 is positive.

y has been replaced with y + 7. We need to write y + 7 as y - k, so we write y - (-7). Then we see that k = -7. The vertical shift is 7 units down since 7 is negative.

Answer: the vertex is (4, -7), choice B.

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2 years ago
Your sister is getting married this summer and she has asked you to help her select a D.J.
ioda
So Dave charges 150 at first and then 10.50 per each hour, so if your sister has the party going for say "h" hours, then his total charges will then be 150 + 10.5h.

now, Marvin's Mobile Music charges 135 at first, but then is more expensive per hour is 15 bucks per each hour, so if she has a party for "h" hours, then his total charges are 135 + 15h.

now, let's check when they're both equal, at how many hours will they cost your sister the same amount.

\bf 150+10.50h=135+15h\implies 150-135=15h-10.5h
\\\\\\
15=4.5h\implies 15=4\frac{1}{2}h\implies 15=\cfrac{9}{2}h\implies \cfrac{15}{\frac{9}{2}}=h\implies \cfrac{\frac{15}{1}}{\frac{9}{2}}=h
\\\\\\
\cfrac{15}{1}\cdot \cfrac{2}{9}=h\implies \cfrac{30}{9}=h\implies \cfrac{10}{3}=h\implies 3\frac{1}{3}=h

so, 3 and a third of a hour, or 3 hours and 20 minutes, they both will cost your sister the same amount, so it wouldn't matter who's hired if the party is only 3 hours and 20 minutes long.

however, after that, the one with higher hourly rate, Marvin's, gets more expensive, and she's better off hiring the one with cheaper hourly rate.

now, you can just get some mp3s and some loud speakers and nevermind the  DJs and you do it, or she can do it, I have the macarena song if you need that one.
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3 years ago
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