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guajiro [1.7K]
3 years ago
6

ormula1" title="(25x + 4 {x}^{2}) \times (36 {y}^{3} )" alt="(25x + 4 {x}^{2}) \times (36 {y}^{3} )" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Reptile [31]3 years ago
5 0
Multiply the terms out:

900xy^{3}  + 144x^{2}y^{3}

You can't do anything else to this because they don't have the same exponents on the variables.
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15% of $70 get it correct for a 100 I need proof first
lana [24]

Answer: 170% da da

Step-by-step explanation:

5 0
3 years ago
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Simplify (-2x^3)^2 x y x y^9
nadezda [96]
Answer: 4x^6y^10
Explanation:
(-2x^3)^2 x y x y^10
= 4x^3 x 2 x y^1+9
4x^6 x y^10
= 4x^6y^10

8 0
3 years ago
What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


8 0
3 years ago
Read 2 more answers
Can anyone find the value of x?​
igomit [66]

Answer:

88.16 units

Step-by-step explanation:

The line at the far left is also = x

For right triangles

   Tan (angle ) = opposite leg / adjacent leg

      for this triangle    tan 10 = x / 500    

                 rearrange to    x = 500 tan 10° = 88.16 units

7 0
2 years ago
Which pairs of angles are congruent?
Burka [1]

Answer:

b) angles 1 and 4 are congruent.

Hope it helps!

8 0
2 years ago
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