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e-lub [12.9K]
3 years ago
7

The formula P = 4s gives the perimeter P of a square with side length s.

Mathematics
1 answer:
12345 [234]3 years ago
6 0

It would be bigger than 1/2 inches because they are simply asking for the difference which is 5 1/2-5= 1/2.

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A shopper is standing on level ground 800 feet from the base of a 250 foot tall department store the shopper looks up and sees a
Aleks04 [339]

Answer:

The elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°

Step-by-step explanation:

From the ΔABC

AB = height of the building = 250 feet

BC = 800 ft

Angle of elevation = \theta

\tan \theta = \frac{AB}{BC}

\tan \theta = \frac{250}{800}

\tan \theta = 0.3125

\theta = 17.35°

Therefore the elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°

8 0
3 years ago
234 divided by 33 I really need this answer doing school work
Elodia [21]

Answer:

7.0909090909 hope this helps!!

4 0
4 years ago
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Which of the following is a non-real complex number?
Nat2105 [25]
A I think Sorry if it’s wrong
8 0
3 years ago
Explain how to find the missing exponent given the base and the value
drek231 [11]

Answer:

To find the value of missing exponent, we have to split the number which is in other side of equal sign (which is not having power) as the multiple of base of the missing exponent.

On both sides, powers have the same base, so their exponents must be equal.

Step-by-step explanation:

<h3>Problem 1:</h3>

Write the missing exponent:

25=5^x

Let x be the missing exponent.

To find the value missing exponent, we have to split the number which is in the left side as the multiple of the base of the missing exponent.

That is,

25=5*5 or 5^2

Now,

5^2=5^x

Powers have the same base so their exponent must be equal.

Hence the missing exponent is 2

6 0
3 years ago
(x+5)(√ 1-x)<br> what is the product of this composite function?
Radda [10]

Answer:

x\sqrt{1-x}+5\sqrt{1-x}

Step-by-step explanation:

(x+5)(\sqrt{1-x} )\\\\=\left(\sqrt{1-x}\right)\left(x+5\right)\\\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\\\a=\left(\sqrt{1-x}\right),\:b=x,\:c=5\\\\=\left(\sqrt{1-x}\right)x+\left(\sqrt{1-x}\right)\times\:5\\\\=x\left(\sqrt{1-x}\right)+5\left(\sqrt{1-x}\right)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\\\=x\sqrt{1-x}+5\sqrt{1-x}

6 0
3 years ago
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