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Mrac [35]
4 years ago
10

Multiple reverberations or reflections of sound can interfere with sound quality. True False

Physics
2 answers:
densk [106]4 years ago
4 0

Multiple reflection causes interference in the sound quality is a TRUE statement.

<u>Explanation: </u>

The reverberation is the cause of interference which is a prolonged sound wave or can also be termed as resonance of sound waves. The sound wave is reflected in an ample amount of time which leads to absorbance of the wave in the medium, therefore, the quality of sound declines in the propagation of the sound wave.

Ivanshal [37]4 years ago
3 0
True I’m pretty sure
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As a result of friction, the angular speed of a wheel changes with time according to dθ/dt = ω0e^−σt where ω0 and σ are constant
NNADVOKAT [17]

Hi there!

a.

We can use the initial conditions to solve for w₀.

It is given that:

\frac{d\theta}{dt} = w_0e^{-\sigma t}

We are given that at t = 0, ω =  3.7 rad/sec. We can plug this into the equation:

\omega(0)= \omega_0e^{-\sigma (0)}\\\\3.7 = \omega_0 (1)\\\\\omega_0 = \boxed{3.7 rad/sec}

Now, we can solve for sigma using the other given condition:

2 = 3.7e^{-\sigma (8.6)}\\\\.541 = e^{-\sigma (8.6)}\\\\ln(.541) = -\sigma (8.6)\\\\\sigma = \frac{ln(.541)}{-8.6} = \boxed{0.0714s^{-1}}

b.

The angular acceleration is the DERIVATIVE of the angular velocity function, so:

\alpha(t) = \frac{d\omega}{dt} = -\sigma\omega_0e^{-\sigma t}\\\\\alpha(t) = -(0.0714)(3.7)e^{-(0.0714) (3)}\\\\\alpha(t) = \boxed{-0.213 rad\sec^2}

c.

The angular displacement is the INTEGRAL of the angular velocity function.

\theta (t) = \int\limits^{t_2}_{t_1} {\omega(t)} \, dt\\\\\theta(t) = \int\limits^{2.5}_{0} {\omega_0e^{-\sigma t}dt\\\\

\theta(t) = -\frac{\omega_0}{\sigma}e^{-\sigma t}\left \| {{t_2=2.5} \atop {t_1=0}} \right.

\theta = -\frac{3.7}{0.0714}e^{-0.0714 t}\left \| {{t_2=2.5} \atop {t_1=0}} \right. \\\\\theta= -\frac{3.7}{0.0714}e^{-0.0714 (2.5)} + \frac{3.7}{0.0714}e^{-0.0714 (0)}

\theta = 8.471 rad

Convert this to rev:

8.471 rad * \frac{1 rev}{2\pi rad} = \boxed{1.348 rev}

d.

We can begin by solving for the time necessary for the angular speed to reach 0 rad/sec.

0 = 3.7e^{-0.0714t}\\\\t = \infty

Evaluate the improper integral:

\theta = \int\limits^{\infty}_{0} {\omega_0e^{-\sigma t}dt\\\\

\lim_{a \to \infty} \theta = -\frac{\omega_0}{\sigma}e^{-\sigma t}\left \| {{t_2=a} \atop {t_1=0}} \right.

\lim_{a \to \infty} \theta = -\frac{3.7}{0.0714}e^{-0.0714a} + \frac{3.7}{0.0714}e^{-0.0714(0)}\\\\ \lim_{a \to \infty} \theta = \frac{3.7}{0.0714}(1) = 51.82 rad

Convert to rev:

51.82 rad * \frac{1rev}{2\pi rad} = \boxed{8.25 rev}

8 0
3 years ago
Being a living example of a tobacco-free lifestyle can __________.
anygoal [31]
Help you live longer.
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4 years ago
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(1) A positive charge +3 C is separated from another positive charge of +5 C by a distance of 7m. What is the magnitude of the e
Aneli [31]

1. The magnitude of the electric force between the two charges is 2.8×10⁹ N (Option B)

2. The net charge on the molecule is -8×10⁻¹⁹ C (Option D)

3. The magnitude of the force between the charges is 16000 N (Option C)

4. The correct statement is: A neutral object has equal numbers of protons and electrons. (Option C)

<h3>1. How to determine the force</h3>
  • Charge 1 (q₁) = +3 C
  • Charge 2 (q₂) = +5 C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 7 m
  • Force (F) =?

F = Kq₁q₂ / r²

F = (9×10⁹ × 3 × 5) / (7)²

F = 2.8×10⁹ N

<h3>2. How to determine the net charge on the molecule</h3>
  • Electron = 223 electrons
  • Proton = 218 protons
  • Net Charge =?

Charge = Proton - Electron

Charge = 218 - 223

Charge = -5 electrons

But

1 electron = 1.6×10⁻¹⁹ C

Thus,

Net Charge = -5 × 1.6×10⁻¹⁹ C

Net Charge = -8×10⁻¹⁹ C

<h3>3. How to determine the force</h3>
  • Charge 1 (q₁) = 2×10⁻⁴ C
  • Charge 2 (q₂) = 8×10⁻⁴ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 0.3 m
  • Force (F) =?

F = Kq₁q₂ / r²

F = (9×10⁹ × 2×10⁻⁴ × 8×10⁻⁴) / (0.3)²

F = 16000 N

<h3>4. What is a neutral object?</h3>

A neutral object is an object having equal numbers of protons and electrons. For example, an object with 4 protons and 4 electrons is said to be neutral as illustrated below

  • Electron = 4 electrons
  • Proton = 4 protons
  • Net Charge =?

Charge = Proton - Electron

Charge = 4 - 4

Charge = 0 (neutral)

Thus, the correct statement about neutral object, given in the question is: A neutral object has equal numbers of protons and electrons (Option C)

Learn more about Coulomb's law:

brainly.com/question/506926

#SPJ1

6 0
2 years ago
Which of the following are considered vectors?
pav-90 [236]

displacement and velocity


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3 years ago
Read 2 more answers
How long would a simple pendulum need to be to have a period of 1. 0s.
Archy [21]

Answer:

0.248 m

Explanation:

5 0
2 years ago
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