For this case, the first thing we must do is define variables.
We have then:
x: number of blue beads
y: number of red beads
We now write the inequations system:
Answer: a system of linear inequations that represents the situation is: 
Step-by-step explanation:
First I do it as separate equations 2x-7=0 and 5x+3=0. In this equation you get two answers so you first answer 2x-7=0
2x-7=0
+7 +7
2x=7
/2 /2
x=7/2
Then do 5x+3=0
-3 -3
5x=-3
/5 /5
x= -3/5
Then you can check by putting them back in.
Answer: a) √50
b) n = 1 + 7i
Step-by-step explanation:
first, the modulus of a complex number z = a + bi is
IzI = √(a^2 + b^2)
The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:
m = 2 + 6i
n = a + bi
Im + nI = 3√10
Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10
= √(a^2 + b^2 + 40) = 3√10
a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90
a^2 + b^2 = 90 - 40 = 50
√(a^2 + b^2 ) = InI = √50
The modulus of n must be equal to the square root of 50.
now we can find any values a and b such a^2 + b^2 = 50.
for example, a = 1 and b = 7
1^2 + 7^2 = 1 + 49 = 50
Then a possible value for n is:
n = 1 + 7i
Answer:
Step-by-step explanation
simplify step-by-step.
2(x+7)−(−18+
4
5
)
Distribute the Negative Sign:
=2(x+7)+−1(−18+
4
5
)
=2(x+7)+(−1)(−18)+−1(
4
5
)
=2(x+7)+18+
−4
5
Distribute:
=(2)(x)+(2)(7)+18+
−4
5
=2x+14+18+
−4
5
Combine Like Terms:
=2x+14+18+
−4
5
=(2x)+(14+18+
−4
5
)
=2x+ 
Answer:
y = 3*(x^2) + 9x -30
Step-by-step explanation:
y=3(x+5)(x-2)
y = (3*x + 3*5) * (x - 2)
y = (3*x + 15) * (x - 2)
y = 3*x*x + 3*x*(-2) + 15*x + 15*(-2)
y = 3*(x^2) - 6x + 15x - 30
y = 3*(x^2) + 9x -30
