Y= (x-2)² + 5. We can write it as : y-5 = (x-2)². The general equation of a quadratic function is :
(y-k) = a(x-h)², where h and k are the vertex of the parabola and a, the coefficient which determines whether the parabola opens upward or downward.
So, y-5 = (x-2)²
Having said that we can say that the VERTEX( 2,5) and since a=1 (a>0) the parabola is open upward OR it passes by a MINIMUM (Then the vertex is minimum)
The domain (x- value) is all Real { x|x = -∞ to x=+∞}
The Range (y-value) is all y ≥ 5
Answer: -7
Step-by-step explanation: y+3x=8x-7
subtract 3x from both sides y=5x-7
y=Mx+b
b=-7
Answer:
I think its uh carrot
Step-by-step explanation:
Answer:
○ C.
Step-by-step explanation:
Wherever the graph intersects the x-axis is considered your zero [x-intercept], therefore you have your answer:
I am joyous to assist you at any time.