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MatroZZZ [7]
3 years ago
15

What the answer to this math problem

Mathematics
1 answer:
olga_2 [115]3 years ago
7 0
The answer is 4.4. C.
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If you do 6-8 you get -2 so all you have to do is add the 3 and its negative. the answer is      .............-32
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John held a garage sale. He priced all the items at a dime or a quarter. His sales totaled
Nikitich [7]

John held a garage sale. He priced all the items at a dime or a quarter, his sales totaled less than $5, the solution is shaded region in quadrant I.

<h3>What is a slope?</h3>

In mathematics, line's slope, also known as its gradient, is a numerical representation of the line's steepness and direction. The letter m is frequently used to represent the slope; reason for this usage is unclear, but it can be found in O'Brien's (1844) and Todhunter's (1888) formulations of equation for a straight line as "y = mx + b" and "y = mx + c," respectively.

He priced all items at a dime or a quarter. His sales totaled less than $5

Since dime =$ 0.10=$0.10 and the quarter =$0.25=$0.25

Let x=x= the number of the items sold for a dime

Let y=y= the number of the items sold for a quarter

0.10x+0.25y<5

0.10x+0.25y<5

Inequality in the slope-intercept form

0.10x+0.25y Subtract 0.10x from both sides

0.25y<-0.10x+5 Divide both sides by 0.25

Subtract 0.10x from both sides

y= -\frac{2}{5}x+20\\

The slope is, -\frac{2}{5} and the y- intercept is 20

Since inequality sign is << so, draw a dashed line

Test point (0,0)(0,0)

Substituting the values 0 for x and 0 for y,

y < -\frac{2}{5}x+20\\\\0 < -\frac{2}{5}(0)+20\\\\0 < +20

Since inequality is true

So, (0,0)(0,0) is solution of the inequality

Shade region containing (0,0)(0,0).

The graph below shows all possible solutions

Since boundary line is dashed and the number of items is always positive

The solution is shaded region in quadrant I

To know more about quadrant visit: brainly.com/question/7196312

#SPJ9

4 0
1 year ago
Can someone give me the answers plz:)
Alborosie

Remark

There is no short way to do this problem and no obvious way to get the answer other that to solve each part.  

Solve

A

\dfrac{x + 1.6}{2} =\text{x + 0.1}                    Multiply by 2

x + 1.6 = 2(x + 0.1)                                         Remove the brackets

x + 1.6 = 2x + 0.1*2                                        

x + 1.6 = 2x + 0.2                                          Subtract x from both sides

1.6 = x + 0.2                                                  Subtract 0.2 from both sides  

1.6 - 0.2 = x                        

1.4 = x

Circle A

B

Subtract 2x from both sides.

3x - 2x = 1.4

Circle B

C

Remove the brackets.

4x + 6 = 2x - 6           Add 6 to both sides

4x + 12 = 2x               Subtract 4x from both sides.

12 = -2x                      Divide by - 2

12/-2 = x

x = - 6                         Don't circle C

D

I'm going to be very scant in my solution of this. You can fill in the steps.

3x = 4.2

x = 4.2/3

x = 1.4

Circle D

5 0
3 years ago
Read 2 more answers
Class A has 15 pupils and class B has 29 pupils.
Vaselesa [24]

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Class A has 15 pupils and class B has 29 pupils. The mean score for class A is 55. Hence:

Mean score of A = (sum of all scores) / 15

55 =  (sum of all scores) / 15

sum of all scores in A = 825

The mean score for both classes is 76. Hence:

[(sum of all scores in A) + (sum of all scores in B)]/(total number of pupils) = mean score of both classes

[825 + (sum of all scores in B)]/(15 + 29) = 76

sum of all scores in B = 2519

Mean score of B = (2519) / 29 = 86.86

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

Find out more on equation at: brainly.com/question/13763238

#SPJ1

6 0
1 year ago
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