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Digiron [165]
3 years ago
9

Which simplified ratio correctly compares 5 meters to 100 centimeters

Mathematics
1 answer:
Greeley [361]3 years ago
5 0
5:1 since 100 cm is = to 1 meter
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the ratio of girls to boys in an astronomy club was 3:2. there were 30 girls. how many total members were there in the club
lakkis [162]

Answer:

Explanation: the ratio 2:4 can be reduced to 1:2, where the number of girls corresponds to the 1 and the number of boys corresponds to the 2. If there are 14 girls, then there must be 28 boys (14 x 2 = 28). Now to get the total number we need to add the total number of boys and girls together. So 14 + 28 = 42

Step-by-step explanation:

5 0
3 years ago
What's 420 seconds to 10 minutes
Neporo4naja [7]
Seventeen (17) minutes!
7 0
3 years ago
Measure the screwdriver's length to the nearest tenth of a centimeter. Express the answer as a decimal.
Alja [10]

Answer:

17.1 cm

Step-by-step explanation:

A screw driver is a mechanical tool or device which is mainly used for screwing the screws and unscrewing them. It is also used for removing the nuts and bolts and also serves a variety of uses.

It is typically made of steel and has a handle and a shaft which ends as a tip.

In the context, the length of the screw driver from the given figure expressed to the nearest tenth of a centimeter is 17.1 cm.

It is also equivalent to $6\frac{3}{4}$ inch.

8 0
3 years ago
What 2 numbers whose sum is 105.7 the numbers are 19, 85.2, 533, 571, 88.2, 525, 20, 17.5, 400, 261, 20.5 ,125, 7, 23, 901, 30
givi [52]
To make it quickly we can consider only those numbers which will give us a decimal of xxx.7. There are only a few numbers like this: 85.2, 88.2, 20.5.
 
I tried adding 85.2 to 17.5 and it gave me 102.5 - it was close but not close enough :)

So I picked 85.2 + 20.5 = 105.7 and voila :)
6 0
2 years ago
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1                    0.1702

28.5                  1.0252

28.8                  0.5077

29.4                   0.0127

29.8                  0.0827

29.8                  0.0827

30.1                   0.3452

30.6                   1.1827

----------------------------------------

236.1                 3.4088

Mean = 236.1 / 8 = 29.51

S_{x}=\sqrt{3.4088/(8-1)}=0.6978

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

t

Finding in the t distribution table α=0.05 with df=7, we have

t_{0.05,7}=2.365

t>-t_{0.05,7} = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

5 0
3 years ago
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