Divide $120 in the ratio 1:2:3

The sum of 3 consecutive even numbers is 66. write an equation and solve to find the smallest even number.

Alekssandra [29.7K]

X+(x+2)+(x+4)= 66
3x+6=66
3x=60
x=20

20,22, and 24. so 20 is the answer

6 0

3 years ago

One teacher wants to give each student 7 over 9 of a slice of pizza. If the teacher has 7 slices of pizza, then how many student

Anna007 [38]

Total = 7 slices.
1student = 7/9 of a slice.

Total number of students:

$7 \div \dfrac{7}{9}$

$= 7 \times \dfrac{9}{7}$

$= 9$

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Answer: She will be able to hand out to 9 students.
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3 0

3 years ago

The rate of change is constant in each table. Find the rate of change. Explain what the rate of change means for the situation.

podryga [215]

Rate of change refers to moving a certain amount of distance over a certain time period
rate of change= velocity in this case.

7 0

3 years ago

Read 2 more answers

Compute the conditional probabilities from the two-way frequency table.

Natali5045456 [20]

Answer:

The table is show clearly in the figure attached.

P(boy if favourite activity is swimming) = 8/17 = 0.47

P(girl if favourite activity is sport) = 7/27 = 0.26

P(girl if favourite activity is reading) = 4/6 = 0.67

P(boy if favourite activity is sport) = 20/27 = 0.74

P(favourite activity is swimming if a girl) = 9/20 = 0.45

P(favourite activity is reading if a boy) = 2/30 = 0.07

P(favourite activity is swimming if a boy) = 8/30 = 0.27

P(favourite activity is reading if a girl) = 4/20 = 0.2

6 0

3 years ago

The Pew Research Center reported that 73% of Americans who own a cell phone also use text messaging. In a recent local survey, 1

AnnZ [28]

Answer:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

Step-by-step explanation:

Information provided

n=200 represent the sample size slected

X=155 represent the cell phone owners used text messaging

$\hat p=\frac{155}{200}=0.775$ estimated proportion of cell phone owners used text messaging

$p_o=0.73$ is the value to verify

$\alpha=0.1$ represent the significance level

We need to conduct a z test for a proportion

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true proportion of cell phone owners used text messaging is different from 0.73 so then the system of hypothesis are:

Null hypothesis: $p=0.73$

Alternative hypothesis: $p \neq 0.73$

The statistic to check this hypothesis is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

6 0

4 years ago