Ask question

Ask question

All categories

3 years ago

6

Compute the conditional probabilities from the two-way frequency table.

1 answer:

Natali5045456 [20]3 years ago

6 0

Answer:

The table is show clearly in the figure attached.

P(boy if favourite activity is swimming) = 8/17 = 0.47

P(girl if favourite activity is sport) = 7/27 = 0.26

P(girl if favourite activity is reading) = 4/6 = 0.67

P(boy if favourite activity is sport) = 20/27 = 0.74

P(favourite activity is swimming if a girl) = 9/20 = 0.45

P(favourite activity is reading if a boy) = 2/30 = 0.07

P(favourite activity is swimming if a boy) = 8/30 = 0.27

P(favourite activity is reading if a girl) = 4/20 = 0.2

You might be interested in

A container in the shape of this cuboid holds 2 litres of water.

zysi [14]

Given:

Volume of cuboid container = 2 litres

The container has a square base.

Its height is double the length of each edge on its base.

To find:

The height of the container.

Solution:

We know that,

1 litre = 1000 cubic cm

2 litre = 2000 cubic cm

Let x be the length of each edge on its base. Then the height of the container is:

$h=2x$

The volume of a cuboid is:

$V=l\times w\times h$

Where, l is length, w is width and h is height.

Putting $V=2000,\ l=x,\ w=x,\ h=2x$ , we get

$2000=x\times x\times 2x$

$2000=2x^3$

Divide both sides by 2.

$1000=x^3$

Taking cube root on both sides.

$\sqrt[3]{1000}=x$

$10=x$

Now, the height of the container is:

$h=2x$

$h=2(10)$

$h=20$

Therefore, the height of the container is 20 cm.

8 0

3 years ago

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$

$T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5$

###

Another way of doing this would be to solve for the coefficients $a,b,c,d,e,g$ in

$f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5$

by expanding the right hand side and matching up terms with the same power of $x$ .

5 0

3 years ago

Simplify the expression. Write the answer using scientific notation. 0.7(3.6x10^-2)

kobusy [5.1K]

The answer would be 2.52×10^-2.

5 0

3 years ago

Read 2 more answers

the measure of angle X WB is x + 3 degrees and the measure of angle B Wy is 3x - 91 degrees solve f or X

Damm [24]

Go on google
and put
operations calculater

3 0

4 years ago

Does anybody know the correct answer?

d1i1m1o1n [39]

Answer:

arithmetic

Step-by-step explanation:

hope it helped

5 0

3 years ago