Answer:
(5x+20)+(4x-11)=180(linear pair)
9x+9=180
9x=180-9
9x=171
x=171/9
x=19
now,
(2y+19)+(5x+20)=180(co-interior angle)
2y+19+5×19+20=180
2y+134=180
2y=180
y=180/2
y=90
Answer:
x° = 37°
Step-by-step explanation:
* Lets revise some facts of a circle
- The secant is a line intersect the circle in two points
- If two secants intersect each other in a point outside the circle,
then the measure of the angle between them is half the difference
of the measures of their intercepted arcs
* Now lets solve the problem
- There is a circle
- Two secants of this circle intersect each other in a point outside
the circle
∴ The measure of the angle between them = 1/2 the difference of the
measures of their intercepted arcs
∵ The measure of the angle between them is x°
∵ The measures of their intercepted arcs are 26° and 100°
- Use the rule above to find x
∴ x° = 1/2 [ measure of the large arc - measure of small arc]
∵ The measure of the large arc is 100°
∵ The measure of the small arc is 26°
∴ x° = 1/2 [100 - 26] = 1/2 [74] = 37°
∴ x° = 37°
Answer:
∠ HGL = 73°
Step-by-step explanation:
KL is a midsegment of the triangle and is parallel to HG, then
∠ KLJ = ∠ HGL ( corresponding angles ), so
9x - 62 = 5x - 2 ( subtract 5x from both sides )
4x - 62 = - 2 ( add 62 to both sides )
4x = 60 ( divide both sides by 4 )
x = 15
Thus
∠ HGL = 5x - 2 = 5(15) - 2 = 75 - 2 = 73°
Answer:
The solution to the system of equations is (1.6,-2)
Step-by-step explanation:
You have to plug the x which is -2 into the equation.
You would get y=2/3(-2)+3
Then you would calculate that to get y=1.6
Lastly you combine the y answer to the x answer to get the coordinates (1.6,-2)
Answer:
Volume of a parallelogram is v=whl
Area of s parallelogram is A= bh
Circumference of a circle= rd
Area of a circle= rd^2
Area of a triangle is 1/a <em>bh</em>
Area of a trapezoid is 1/2(b1 + b2)h
Perimeter of a quadrilateral is 2L + 2W
I couldn't drag the image but I knew what I was doing!
