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Aleonysh [2.5K]
3 years ago
12

If a company buys an item at a wholesale price of $45, which of the following would make sense as a retail price to charge the c

ustomers? Choose ALL that apply! $80 $60 $20 $40
Mathematics
1 answer:
boyakko [2]3 years ago
4 0

Answer:

Step-by-step explanation:

buys it for $ 45

well...you know the business is gonna want to make a profit...so they would have to sell it for more then they bought it for.

I would say $ 60 or $ 80

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After 3 hours of of driving, Paul had gone 183 miles. What was his average rate of speed? Explain your answer.
snow_lady [41]

Answer:

The average rate of speed is 61!

Step-by-step explanation:

183 miles divided by 3 hours of driving is 61 average rate of speed. :)

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WILL DO ABSOLUTELY ANYTHING FOR THIS ONE HELP ASAP TIMES
Rina8888 [55]

Given:

The graph of a function y=h(x).

To find:

The interval where h(x)>0.

Solution:

From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So, h(x)>0 for x and x>3.6.

The function between x=0 and x=3.6 lies below the x-axis. So, h(x) for 0.

Now,

For -1, the graph of h(x) is above the x-axis. So, h(x)>0.

For 0, the graph of h(x) is below the x-axis. So, h(x).

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Therefore, the correct option is A.

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2 years ago
Use the estimates to help you choose each correct answer. 14.8(20.7) = Estimate: 15(20) = 300 1.1(9.8) = Estimate: 1(10) = 10 72
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Answer:

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Step-by-step explanation:

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3 years ago
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Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

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Answer:

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Step-by-step explanation:

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