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Sati [7]
1 year ago
9

Let x and y be directly related such that y = 9 when x = 3. Find y when x = 7.

Mathematics
1 answer:
beks73 [17]1 year ago
3 0

Answer:

y=21

Step-by-step explanation:

y= 9 cos x =3 so y=3 when x=1 on the base level so if x=7 would be x=1 on the base level * 7 then y=3 on the base level * 7 would be y = 21

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Find the diameter of a circle with a circumference of 443 feet. Use 3.14 for pi.
marishachu [46]

Answer:

\huge\boxed{\sf d = 141\ feet}

Step-by-step explanation:

<u>Given Data:</u>

Circumference = C = 443 ft

<u>Required:</u>

Diameter = d = ?

<u>Formula:</u>

d = C / π

<u>Solution:</u>

d = 443 / 3.14

d = 141.0 feet

d = 141 feet

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
3 0
2 years ago
Read 2 more answers
Me podrían ayudar con esto?​
xxTIMURxx [149]

Answer:

0

Step-by-step explanation:

This would be basically be zero/0 because anything times 0 is just nothing.

7 0
1 year ago
Simplify the expression.
Neporo4naja [7]

Answer:

D

Step-by-step explanation:

3 0
1 year ago
What is the right way to use substitution method?​
Kazeer [188]

Answer:

Step-by-step explanation:

Substitution method can be applied in four steps. Step 1: Solve one of the equations for either x = or y = . Step 2: Substitute the solution from step 1 into the other equation. Step 3: Solve this new equation Happy too help!

7 0
3 years ago
Using traditional methods it takes 92 hours to receive an advanced flying license. A new training technique using Computer Aided
DanielleElmas [232]

Answer:

The value of the test statistic is z = 1.39.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

Step-by-step explanation:

Using traditional methods it takes 92 hours to receive an advanced flying license.

This means that at the null hypothesis, it is tested if the mean is of 92, that is:

H_0: \mu = 92

Test if there is evidence that the technique lengthens the training time

At the alternative hypothesis, it is tested if the mean is more than 92, that is:

H_1: \mu > 92

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

92 is tested at the null hypothesis:

This means that \mu = 92

A researcher used the technique on 70 students and observed that they had a mean of 93 hours. Assume the population variance is known to be 36.

This means that n = 70, X = 93, \sigma = \sqrt{36} = 6

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{93 - 92}{\frac{6}{\sqrt{70}}}

z = 1.39

The value of the test statistic is z = 1.39.

P-value of the test and decision:

The p-value of the test is the probability of finding a sample mean above 93, which is 1 subtracted by the p-value of z = 1.39.

Looking at the z-table, z = 1.39 has a p-value of 0.9177.

1 - 0.9177 = 0.0823.

The p-value of the test is 0.0823 > 0.05, which means that there is not evidence at the 0.05 level that the technique lengthens the training time.

8 0
2 years ago
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