Question

Two urns contain white balls and yellow balls. The first urn contains 2 white balls and 7 yellow balls and the second urn contains 10 white balls and 4 yellow balls. A ball is drawn at random from each urn. What is the probability that both balls are white?

Answer 1

Answer with Step-by-step explanation:

A: white ball is drawn from first urn

P(A)=number of white balls in first urn/total balls in first urn

      = 2/9

B: white ball is drawn from second urn

P(B)=number of white balls in second urn/total balls in second urn

      = 10/14

A∩B: white ball is drawn from both urns

Since, events A and B are independent

Hence, P(A∩B)=P(A)×P(B)

                        =$\dfrac{2}{9}\times \dfrac{10}{14}$

                        = 10/63

Hence, probability that both balls are white is:

10/63

Answer 2

P(WW)=(2/9)(10/14)

P(WW)=10/63